从词典列表创建唯一的词典列表，该词典列表包含相同的键但值不同 [英] Creating a unique list of dictionaries from a list of dictionaries which contains same keys but different values

问题描述

假设我得到了这样的词典列表:

suppose i have been given a list of dictionaries like this :

[{"id":1, "symbol":'A', "num":4}, {"id":2, "symbol":'A', "num":3}, {"id":1, "symbol":'A', "num":5}, {"id":2, "symbol":'B', "num":1}]

现在，我必须创建一个字典或更改当前字典，以使(id，symbol)一起唯一，并且num值是字典中具有该(id，symbol)的所有值的总和，以便新字典或当前字典看起来像这样:

Now, i have to create a dictionary or alter the current one such that (id, symbol) together are unique and the num value is the sum of all the values present in the dict with that (id,symbol) so that the new dict or the current dict looks something like this:

[{"id":1, "symbol":'A', "num":9}, {"id":2, "symbol":'A', "num":3}, {"id":2, "symbol":'B', "num":1}]

推荐答案

这是使用纯Python的解决方案.

Here's a solution with plain python.

dlst = [{"id":1, "symbol":'A', "num":4}, {"id":2, "symbol":'A', "num":3},
    {"id":1, "symbol":'A', "num":5}, {"id":2, "symbol":'B', "num":1}]


# Create a dict where keys are tuples of (id,symbol), values are num

combined_d = {}

for d in dlst:
    id_sym = (d["id"], d["symbol"])
    if id_sym in combined_d:
        combined_d[id_sym] += d["num"]
    else:
        combined_d[id_sym] = d["num"]

# create a list of dictionaries from the tuple-keyed dict

result = []

for k, v in combined_d.items():
    d = {"id": k[0], "symbol": k[1], "num": v}
    result.append(d)

print(result)

它可以做您想要的，但是结果列表没有排序，因为它是根据字典构建的.

It does what you want, but the resulting list is not sorted, as it's built from a dictionary.

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