按值对Swift字典数组进行排序 [英] Sort Swift array of dictionaries by value

问题描述

按值对[String : String]数组进行排序的最好，最有效的方法是什么?

What is the best and most efficient way sorting an array of [String : String] by value?

例如

let dicts = [["key": "4"], ["key": "4"], ["key": "3"], ["key":"1"]]

然后我要排序

dicts = [["key": "1"], ["key": "3"], ["key": "4"], ["key":"4"]]

推荐答案

虽然有些罗word，但可以很好地控制丢失的键和非整数值.

It's a little wordy, but it get you at good control of missing keys and non-int values.

var array = [["key": "1"], ["key": "3"], ["key": "2"], ["key":"4"]]
array.sort { (lhs, rhs) -> Bool in
    if let leftValue = lhs["key"], let leftInt = Int(leftValue), let rightValue = rhs["key"], let rightInt = Int(rightValue) {
        return leftInt < rightInt
    } else {
        return false // NOTE: you will need to decide how to handle missing keys and non-int values.
    }
}

如果您比较比较灵活，并且想要一些更清洁的东西.

If your a bit more flexible about the compare and want something a little cleaner.

array.sort {
    guard let leftValue = $0["key"], let rightValue = $1["key"] else {
        return false // NOTE: you will need to decide how to handle missing keys.
    }

    return leftValue.localizedStandardCompare(rightValue) == .orderedAscending
}

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