从C ++中的char *获取C#中的byte [] [英] Get byte[] in C# from char* in C++

问题描述

在C#中，我有一个数据类型byte[]，我想使用返回char*

In C# I have an data type byte[], which I want to fill in using a C++ function which returns char*

C ++函数(在ImageData.dll中)

The C++ function (in ImageData.dll)

char* pMemoryBuffer = NULL;
char* LoadData(const char *fileName)
{
    // processing pMemoryBuffer ...
    return pMemoryBuffer;  
}

将本机dll导入C#:

Import native dll into C#:

    [DllImport(".\\Modules_Native\\ImageData.dll", EntryPoint = "LoadData")]
   private extern static byte[] LoadData(string fileName);

C#中的byte[]数据

byte[] buffer = new byte[256*256];
buffer = LoadData("D:\\myPic.tif");

显然它还没有工作，但是它提出了我想做什么的想法.所以我想知道如何使这项工作，以及正确的方法是什么.非常感谢您的教育.

Apparently it is not working yet, but it presents the idea of what I want to do. So I am wondering how to make this work, and what is the right way to do it. Thanks very much for your education.

推荐答案

尝试一下

// c++

    void LoadData(unsigned char* *pMemoryBuffer, const char *fileName)
    {
        // processing pMemoryBuffer ...
        *pMemoryBuffer = resutss;

    }

将本机dll导入C#:

Import native dll into C#:

[DllImport(".\\Modules_Native\\ImageData.dll", EntryPoint = "LoadData")]
private extern static void LoadData(out IntPtr data, string fileName);

当函数返回数据时，它将指向数组，您可以使用Marshal类读取内容.我想您会将其复制到新的字节arra y.

When the function returns data will point to the array and you can read the contents using the Marshal class. I guess you would copy it to a new byte array.

byte[] buffer = new byte[256*256];
buffer = Marshal.Copy(LoadData(buffer ,"D:\\myPic.tif"), buffer , 0, buffer.Length);

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