在MASM中获取结构尺寸 [英] Get structure size within MASM

问题描述

我想知道如何在MASM编译时获取结构的大小.

I am wondering how to get the size of a structure at compilation time in MASM.

这是C的等效代码.

struct Point
{
  int x;
  int y;
};

printf("Point Stucture size %d\n", sizeof(struct Point));

推荐答案

我假设您将在汇编代码中声明该结构.
根据masm32文档，您可以使用以下运算符给你:

I'm assuming that you'll be declaring the struct in your assembly code.
According to the masm32 documentation you've got the following operators available to you:

LENGTHOF variable

SIZEOF variable

SIZEOF type

LENGTH expression

SIZE expression

说明

LENGTHOF运算符返回分配给<variable>的数据项的数量. SIZEOF运算符返回分配给<variable>的字节总数或<type>的大小(以字节为单位).对于变量，SIZEOF等于LENGTHOF的值乘以每个元素中的字节数.

The LENGTHOF operator returns the number of data items allocated for <variable>. The SIZEOF operator returns the total number of bytes allocated for <variable> or the size of <type> in bytes. For variables, SIZEOF is equal to the value of LENGTHOF times the number of bytes in each element.

允许LENGTH和SIZE运算符与以前版本的汇编程序兼容.当应用于数据标签时，LENGTH运算符将返回由DUP运算符创建的元素数.否则返回1.应用于数据标签时，SIZE运算符将返回第一个初始化程序在<variable>标签处分配的字节数.

The LENGTH and SIZE operators are allowed for compatibility with previous versions of the assembler. When applied to a data label, the LENGTH operator returns the number of elements created by the DUP operator; otherwise it returns 1. When applied to a data label, the SIZE operator returns the number of bytes allocated by the first initializer at the <variable> label.

MASM 6.1中的LENGTHOF和SIZEOF运算符更一致地处理数组.这些运算符返回初始化项中的数据项数和字节数.

The LENGTHOF and SIZEOF operators in MASM 6.1 handle arrays much more consistently. These operators return the number of data items and the number of bytes in an initializer.

请参阅masm32/help目录中的masm32.chm.

See masm32.chm in the masm32/help directory.

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