以任何顺序匹配正则表达式 [英] Match regex in any order

问题描述

我想用正则表达式检查复杂的密码.

I want to check for complex password with regular expression.

它应该具有1个数字1个大写字母和一个小写字母，而不是特定的顺序. 所以我虽然这样:

It should have 1 number 1 uppercase and one lowercase letter, not in specific order. So i though about something like this:

m = re.search(r"([a-z])([A-Z])(\d)", "1Az")
print(m.group())

但是我不知道如何告诉他以任何顺序进行搜索. 我尝试浏览网络，但没有找到有趣的东西，谢谢您的帮助.

But i don't know how to tell him to search in any order. I tried to look on web but I didn't found something interesting, thanks for help.

推荐答案

您本可以尝试查找用于验证正则表达式的密码，该站点上有很多;)

You could have tried looking for password validating regex, the site has a lot of them ;)

也就是说，您可以使用积极前瞻来做到这一点:

That said, you can use positive lookaheads to do that:

re.search(r"(?=.*[a-z])(?=.*[A-Z])(?=.*\d)", "1Az")

实际上要匹配字符串...

And to actually match the string...

re.search(r"(?=.*[a-z])(?=.*[A-Z])(?=.*\d).{3}", "1Az")

现在，确保密码长度为3个字符:

And now, to ensure that the password is 3 chars long:

re.search(r"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d).{3}$", "1Az")

正向超前(?= ... )确保要测试的字符串中存在表达式.因此，字符串必须具有小写字符((?=.*[a-z]))，大写字符((?=.*[A-Z]))和数字((?=.*\d))，以使正则表达式能够通过".

A positive lookahead (?= ... ) makes sure the expression inside is present in the string to be tested. So, the string has to have a lowercase character ((?=.*[a-z])), an uppercase character ((?=.*[A-Z])) and a digit ((?=.*\d)) for the regex to 'pass'.

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