如何使用与号(&)替换匹配模式中的字符 [英] How to replace a character within a matched pattern using ampersand (&)

问题描述

当我们使用sed匹配模式时，匹配的模式存储在&"变量中.有没有办法使用&符本身替换此匹配模式中的字符?

When we match a pattern using sed, the matched pattern is stored in the "ampersand" (&) variable. IS there a way to replace a character in this matched pattern using the ampersand itself ?

例如，如果&包含字符串"apple1"，该如何使用&将字符串设置为"apple2"(即1替换为2)?

For example, if & contains the string "apple1", how can I use & to make the string to "apple2" (i.e replace 1 by 2) ?

推荐答案

如果我猜对了，那么您想要做的就是以匹配的模式应用替换.您不能使用&来执行此操作.您要改为执行此操作:

If I guessed right, what you want to do is to apply a subsitution in a pattern matched. You can't do that using &. You want to do this instead:

echo apple1 apple3 apple1 apple2 botemo1 | sed '/apple./ { s/apple1/apple2/g; }'

这意味着您只想在与模式/apple./匹配的行上执行命令替换.

This means that you want to execute the command substitution only on the lines that matches the pattern /apple./.

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