使用正则表达式忽略带有数字的字符串中的日期 [英] Ignore date in a string with numbers using regular expression
问题描述
我有一个小问题.
我使用[0-9\,.]*
查找字符串中的小数.
然后([^\s]+)查找第一个数字后面的文本.
i use [0-9\,.]*
to finde a decimal in a string.
And ([^\s]+) to find the text behind the first number.
字符串通常看起来像这样. 1个数字，而不是日期:
The string looks normally like this. 1 number a text and than a date:
1.023,45stück
1.023,45 stück
24.05.10
但是有时我只有日期，然后我变成240510(十进制). 有时我只有十进制数.
but sometimes I had just the date and then i become 240510 as decimal. And sometimes I had just the decimal.
我应该如何修改正则表达式以查找日期(如果存在)并将其删除? 然后寻找一个小数，如果存在则选择一个.
How should I modify the regex to find the date if existing and remove it? And then look for a decimal an select this if existing.
谢谢.
推荐答案
分而治之
-
先检查日期，然后从字符串中删除匹配项
Check for the date first and remove the match from the string
([0-9]{1,2}\.){2}[0-9]{1,2}
使用原始正则表达式查找号码
Find the number using your original regex
[0-9\,.]*
如果需要，可以找到数量单位(假设u Umlaut仅将其小写)
If you need it find the unit of quantity (assuming that you will only have it as lower case with u Umlaut)
([a-zü]+)
请参见 http://regexe.de/(德语)和
See http://regexe.de/ (German) and http://www.regexr.com/ (English) for some useful information and tools for dealing with regex.
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