///android_asset/www/apis/camera.js：在文件无法读取未定义类型的属性格式“DATA_URL”45 [英] Can not read propery 'DATA_URL' of undefined type at file:///android_asset/www/apis/camera.js:45
问题描述
我非常新的PhoneGap应用程序，但我的机器人developer.I我试图调用摄像头在我的PhoneGap application.Following点击一个按钮是我的html在那里我打电话take_pic（）API camera.js方法javascript.I只看到API的例子后，包括身体camera.js。
＆LT;身体GT;
＆LT;标签=你好＆GT;的Hello World＆LT; /标签＆gt;
＆LT; BR＆GT;＆LT;输入类型=提交ID =提交值=通话摄像头的onclick =take_pic（）;＆GT;
＆LT;脚本类型=文/ JavaScript的字符集=utf-8SRC =的API / camera.js＆GT;＆LT; / SCRIPT＆GT;
＆LT; /身体GT;
以下是这也是引发camera.js的方法，但它会抛出在文件无法读取未定义类型的属性格式DATA_URL'：///android_asset/www/apis/camera.js：45的错误。请家伙帮我out.let我知道，如果需要更多的细节。
函数take_pic（）{
navigator.camera.getPicture（onPhotoDataSuccess，函数（前）{
警报（相机错误！）;
}，{质量：30，destinationType：destinationType.DATA_URL}）;
}
你试下code？它是在PhoneGap的API的例子： PhoneGap的例子
VAR pictureSource; //图片来源
VAR destinationType; //设置返回值的格式//等待设备API库加载
//
document.addEventListener（deviceready，onDeviceReady，FALSE）;//设备API可用
//
功能onDeviceReady（）{
pictureSource = navigator.camera.PictureSourceType;
destinationType = navigator.camera.DestinationType;
}功能take_pic（）{
navigator.camera.getPicture（onPhotoDataSuccess，函数（前）{
警报（相机错误！）;
}，{质量：30，destinationType：destinationType.DATA_URL}）;
}
我觉得你的问题是变量destinationType是不确定的。你有没有正确初始化呢？
I am very much new to phonegap applications but i am an android developer.I am trying to call camera on a button click in my phonegap application.Following is my html where i am calling take_pic() method of camera.js api javascript.I have included camera.js in body after seeing api example only.
<body>
<label for="hello">Hello World</label>
<br><input type="submit" id="submit" value="Call Camera" onclick="take_pic();">
<script type="text/javascript" charset="utf-8" src="apis/camera.js"></script>
</body>
following is the method of camera.js which is triggered but it throws "Can not read propery 'DATA_URL' of undefined type at file:///android_asset/www/apis/camera.js:45" error .Please guys help me out.let me know if more details are required
function take_pic() {
navigator.camera.getPicture(onPhotoDataSuccess, function(ex) {
alert("Camera Error!");
}, { quality : 30, destinationType: destinationType.DATA_URL });
}
Did you try the next code? it is in the PhoneGap API examples: PhoneGap example
var pictureSource; // picture source
var destinationType; // sets the format of returned value
// Wait for device API libraries to load
//
document.addEventListener("deviceready",onDeviceReady,false);
// device APIs are available
//
function onDeviceReady() {
pictureSource=navigator.camera.PictureSourceType;
destinationType=navigator.camera.DestinationType;
}
function take_pic() {
navigator.camera.getPicture(onPhotoDataSuccess, function(ex) {
alert("Camera Error!");
}, { quality : 30, destinationType: destinationType.DATA_URL });
}
I think your problem is that the variable "destinationType" is undefined. Did you initialized it properly?
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