将矩阵折叠成列 [英] Collapsing matrix into columns

问题描述

我有一个2D矩阵，其中列数始终是3的倍数(例如250×27)-由于结果的重复组织(A,B,C，A,B,C，A,B,C等) ).我希望重塑此矩阵，以创建一个具有3列的新矩阵-每列包含每种类型(A,B,C)(例如2250×3)的汇总数据.

I have a 2D matrix where the № of columns is always a multiple of 3 (e.g. 250×27) - due to a repeating organisation of the results (A,B,C, A,B,C, A,B,C, and so forth). I wish to reshape this matrix to create a new matrix with 3 columns - each containing the aggregated data for each type (A,B,C) (e.g. 2250×3).

因此在250×27的矩阵中，列1,4,7,10,13,16,19,22,25中的所有数据将合并以形成最终重整矩阵的第一列.

So in a matrix of 250×27, all the data in columns 1,4,7,10,13,16,19,22,25 would be merged to form the first column of the resulting reshaped matrix.

结果整形矩阵中的第二列将包含列2,5,8,11,14,17,20,23,26中的所有数据-依此类推.

The second column in the resulting reshaped matrix would contain all the data from columns 2,5,8,11,14,17,20,23,26 - and so forth.

在MATLAB中有一种简单的方法吗?我只知道如果要合并的列是相邻的(1,2,3,4,5,6)而不是不相邻的(1,4,7,10,13,16)等，如何使用reshape.

Is there a simple way to do this in MATLAB? I only know how to use reshape if the columns I wanted to merge were adjacent (1,2,3,4,5,6) rather than non-adjacent (1,4,7,10,13,16) etc.

推荐答案

从 @Divakar 的无耻偷窃:

B = reshape( permute( reshape(A,size(A,1),3,[]), [1,3,2]), [], 3 );

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