加入多首曲目时匹配音频持续时间 [英] Match audio duration when joining multiple tracks

问题描述

我有一个将音轨组合在一起的程序，当前的系统是我可以编写两个音轨并使它们同时播放.我遇到的问题是，它只能在最短的轨道上播放，例如:

I have a program that combines audio tracks together, the current system I have is that I can write two audio tracks and make them play simultaneously. The problem I am having is that it only plays for the duration of the shortest track, so for instance:

曲目1的持续时间= 2:00

Track 1's duration = 2:00

Track 2的持续时间= 1:12

Track 2's duration = 1:12

仅当我要为2:00(全长)播放时，它才为1:12播放.解决此问题的最佳方法是什么?

It will only play for 1:12 when I want it to play for 2:00 (the whole length). What's the best way to go about solving this issue?

到目前为止，我的解决方案是

My solution so far:

length = min([length(s1), length(s2)]);

s1 = s1(1:length);
s2 = s2(1:length);
s3 = s1 + s2;

推荐答案

首先不要使用函数名称"length"来定义新变量，您将无法在下一条语句中将其用作函数. 其次，当您播放多首曲目时，您希望一开始就可以进行某种同步，因此我为您添加了此选项.

First of all don't use function name "length" as to define new variable, You will not be able to use it as function in the next statement. Second, when you play multiple tracks you want to be able to do some kind of sync in the beginning, so i added for you this option.

解决方案是这样的:

s1=[ 0.5, 0.2, 0.2, 0.1 ];
s2=[ 0.1, 0.4 ];

s1_pad_delay=8; s1_pad_after=5;
s2_pad_delay=4; s2_pad_after=3;

s1_len=s1_pad_delay+length(s1)+s1_pad_after;
s2_len=s2_pad_delay+length(s2)+s2_pad_after;
mix_len=max(s1_len,s2_len);

s1_padded=[ zeros(1,s1_pad_delay), s1, zeros(1,mix_len-length(s1)-s1_pad_delay) ];
s2_padded=[ zeros(1,s2_pad_delay), s2, zeros(1,mix_len-length(s2)-s2_pad_delay) ];

mix=s1_padded+s2_padded

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