在Matlab中将纪元转换为日期 [英] Converting Epoch to Date in Matlab
问题描述
我在Matlab中有一个历元数组(数字数组).我想将它们转换为UTC日期时间格式,例如DD-MM-YYYY HH:MM.
I have an array of Epoch milliseconds (array of numbers) in Matlab. I would like to convert these into UTC date-time format, such as DD-MM-YYYY HH:MM.
是否有预定义的Matlab方法可以做到这一点?还是我必须编写自己的函数?
Is there a pre-defined Matlab way to do this or will I have to write my own function?
推荐答案
假设您从向量time_unix
开始,然后:
Suppose, you start with a vector time_unix
, then:
>> time_unix = 1339116554872; % example time
>> time_reference = datenum('1970', 'yyyy');
>> time_matlab = time_reference + time_unix / 8.64e7;
>> time_matlab_string = datestr(time_matlab, 'yyyymmdd HH:MM:SS.FFF')
time_matlab_string =
20120608 00:49:14.872
注意:
1)参见matlab时间的定义.
1) See the definition of matlab's time.
2)8.64e7是一天中的毫秒数.
2) 8.64e7 is number of milliseconds in a day.
3)Matlab不应用任何时区偏移,因此结果是相同的UTC时间.
3) Matlab does not apply any time-zone shifts, so the result is the same UTC time.
4)向后转换示例:
>> matlab_time = now;
>> unix_time = round(8.64e7 * (matlab_time - datenum('1970', 'yyyy')))
unix_time =
1339118367664
总结一下,这是两个功能:
To summarize, here are two functions:
function tm = unix2matlab(tu)
tm = datenum('1970', 'yyyy') + tu / 864e5;
end
function tu = matlab2unix(tm)
tu = round(864e5 * (tm - datenum('1970', 'yyyy')));
end
此处的Matlab时间为数字.您始终可以使用datestr()将其转换为字符串
The matlab time here is numeric. You can always convert it to string using datestr()
更新纳秒
time_unix_nanos = 1339116554872666666;
millis = round(time_unix_nanos / 1e6);
nanos = time_unix_nanos - 1e6 * millis;
time_matlab = unix2matlab(millis);
s = [datestr(time_matlab, 'yyyymmdd HH:MM:SS.FFF'), num2str(nanos)];
s =
20120608 00:49:14.872666666
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