将嵌套的结构数组重塑为具有大小不同的元素的单元格数组 [英] Reshaping nested struct arrays to cell array having elements with different sizes

问题描述

我对我的

I have a similar question to my previous one. This time the form of the nested structure looks like this:

Sizes = [2, 5, 8, 6, 3];
cells = 5;
for i = 1:cells
    for j = 1:Sizes(i)
        a(i).b.c(j).d = rand(1,1);
    end
    a(i).b.Size = Sizes(i);
end

同样，我想将a(:).b.c(:)的所有d值放入包含1 x cells单元格的单个cell array中.

Again I would like to put all the d values of a(:).b.c(:) into a single cell array that contains 1 x cells cells.

这是我使用cellfun的解决方案，但我想避免使用此功能:

Here is my solution using cellfun but I would like to avoid this function:

ab = [a.b];
abc = {ab.c};
abcd = cellfun(@(x) [x.d], abc, 'UniformOutput', false);

对abc使用以前的解决方案:

Using the previous solution for abc:

abc = [ab.c];

使用字段d创建一个1x24结构数组.我曾考虑过使用Size字段将结果重塑为cell array，但我不知道如何或是否有可能.如果没有使用循环并且没有cellfun，您是否有更好的方法?

creates a 1x24 struct array with field d. I thought of using the Size field to reshape this result into a cell array but I don't know how or if it is possible. Do you have a better appraoch without using loops and without cellfun?

推荐答案

您可以使用

You can do this using mat2cell as follows:

ab = [a.b];
abc = [ab.c];
abcd = mat2cell([abc.d], 1, [ab.Size]);

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