用NaN加2x2矩阵 [英] Adding 2x2 matrix with NaNs

问题描述

除了寻求编程建议外，MATLAB的一般性问题还不多-如果我有:

More of a general MATLAB question than looking for programming advice -- if I have:

y = cellfun(@(x)sum(x(:)), Z, 'un', 0);

其中每个单元格矩阵中都有NaN和实数的组合，当我对每个单元格中这些矩阵的所有元素求和时，我总会得到total = NaN，因为存在NaN在那儿，否则它们将被忽略而只是对实数求和.我问的原因是因为我越来越:

where there are a combinations of NaN's and real numbers in each cell matrix, when I sum all elements of those matrices per cell, will I always get total = NaN because there are NaN's in there, or will they be ignored and just sum the real numbers. The reason I ask is because I am getting:

y = [NaN] [NaN] [NaN]
    [NaN] [NaN] [NaN]
    [NaN] [NaN] [NaN]

一个示例单元矩阵(单元元素)为:

an example cell matrix (cell element) would be:

x{1,1} = NaN 2   3
         4   5   6
         7   8   9

所以我希望y的第一个元素是:

so I would expect the first element of y to be:

y{1,1} = 44

我怎么不知道这个?

推荐答案

要忽略NaN，只需在您的匿名函数中使用矢量索引，方法是替换冒号(:)
与~isnan(x):

To ignore the NaNs, just use vector indexing in your anonymous function, by replacing the colon (:)
with ~isnan(x):

@(x)sum(x(~isnan(x)))

所以您得到:

y = cellfun(@(x)sum(x(~isnan(x))), Z, 'un', 0);

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