在MATLAB中将值分配给结构数组的字段 [英] assigning values to a field of an structure array in MATLAB

问题描述

我想替换结构数组中字段的值.例如，在以下结构中，我想将所有1替换为3.

I want to replace the value of the fields in a structure array. For example, I want to replace all 1's with 3's in the following construction.

a(1).b = 1;
a(2).b = 2;
a(3).b = 1;

a([a.b] == 1).b = 3; % This doesn't work and spits out:
% "Insufficient outputs from right hand side to satisfy comma separated
% list expansion on left hand side.  Missing [] are the most likely cause."

是否有简单的语法?我想避免此类简单操作的for循环.

Is there an easy syntax for this? I want to avoid ugly for loops for such simple operation.

推荐答案

信用归@Slayton所有，但实际上您也可以使用

Credits go to @Slayton, but you actually can do the same thing for assigning values too, using deal:

[a([a.b]==1).b]=deal(3)

那么细分:

[a.b]

检索数组a的所有b字段，并将其放入逗号分隔列表.

retrieves all b fields of the array a and puts this comma-separated-list in an array.

a([a.b]==1)

使用逻辑索引仅索引a满足约束的元素.随后，上面的完整命令根据3分配给结果逗号分隔列表的所有元素.html#br2js35-8"rel =" noreferrer>此.

uses logical indexing to index only the elements of a that satisfy the constraint. Subsequently the full command above assigns the value 3 to all elements of the resulting comma-separated-list according to this.

这篇关于在MATLAB中将值分配给结构数组的字段的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！