Simulink-每30秒输出1，否则输出0 [英] Simulink - Output 1 every 30 seconds, 0 otherwise

问题描述

我需要一个子系统，该子系统需要每隔30秒或30秒或更短的时间输出1.

I need a subsystem that needs to output 1 at interval or 30 seconds or slightly over 30 seconds.

用matlab代码编写，应该可以这样工作

Written in matlab code it should work like that

function y = fcn(time,uplinkTimeInterval)

%#codegen

persistent lastTriggerTime

if isempty(lastTriggerTime)

    lastTriggerTime = 0;

end 

if time>=lastTriggerTime || time == 0

    y = 1;

    lastTriggerTime = time + uplinkTimeInterval;
else

    y = 0;

end

end

其中ulplinkTimeInterval是30秒.当然，我尝试将此代码与matlab功能块一起使用，但是由于某种原因它不起作用(在调试模式下，我可以看到y取值1，但它只是不将值输出到块外)，因此我想使用积木，但我不知道该怎么做.

where ulplinkTimeInterval is 30 seconds. Of course I tried to use the matlab function block with this code but for some reason it does not work (in debug mode I can see that y takes value 1 as it should but it simply does not ouput the value outside the block), therefore I wanted to use blocks but I do not know how to do it.

非常感谢您的帮助

推荐答案

您可以使用代码或块使此逻辑相对容易.当您请求使用块的解决方案时，就在这里！

You can make this logic relatively easily with code or blocks. As you requested a solution using blocks, here it is!

• 使用clock块来跟踪时间，并使用某些constant块来确定给出1而不是0的间隔(以秒为单位).
• 使用memory块将clock信号延迟1个时间步长，因此我们可以比较连续步长的值.
• 将时间除以间隔，然后四舍五入，以给出许多间隔的过去时间.
• 最后，使用relational operator比较连续的经过的间隔数".如果更多的间隔已通过上限，则您刚刚超过了间隔阈值.

• Use the clock block to keep track of time, and some constant block to determine the interval (in seconds) at which to give 1 instead of 0.
• Use the memory block to delay the clock signal by 1 timestep, so we can compare consecutive steps' values.
• Divide the times by the interval, and round down, to give how many intervals have passed.
• Finally, compare consecutive "number of intervals passed" using a relational operator. If more intervals have passed on the upper line, then you have just stepped over the interval threshold.

注意:对于尚未跨越新间隔的每个时间步，这将返回0，而对于每个单独的时间步，将返回1.输出的准确性将取决于模型的步长.

Note: this will return a 0 for every timestep where you have not crossed a new interval, and a 1 at each individual timestep where you have. The accuracy of the output will depend on the step size of your model.

将memory块添加到floor块之后可能会更清楚/更容易，因此您只需进行除法/舍入一次.它仍然可以让您与上一个时间步进行比较.看起来像:

It may be clearer / easier to just add the memory block after the floor block, so you are only doing the division / rounding once. It would still allow you to do a comparison to the previous time step. That would look like:

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