将3维数组重塑为2维 [英] Reshaping a 3 dimensional array to 2 dimensions

问题描述

我有一个尺寸为427x470x48的3维矩阵

I have a 3-dimensional matrix of dimensions: 427x470x48

我想将其重塑为二维尺寸矩阵:48x200690

I want to reshape this into a 2-dimensional matrix of dimensions: 48x200690

这意味着old(1，1，:)对应于new(:, 1)

This would mean that old(1, 1, :) would correspond to new(:, 1)

此外，old(1,2，:)对应于new(:，2)，依此类推.

Additionally, old(1,2,:) would correspond to new(:,2) and so on and so forth.

谢谢

推荐答案

执行:

new = reshape(permute(old, [3 2 1]), 48, []);

您还可以通过以下方式粗略检查它们是否相等:

Also you can roughly check that they are equal by:

numel(intersect(old(1,1,:),new(:,1))) == 48;

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