用bsxfun将一个矩阵的所有列乘以另一个矩阵 [英] Multiply all columns of one matrix by another matrix with bsxfun

问题描述

我有两个矩阵A和B，大小均为4x4.将A的第一列与B的所有其他列乘以

I have two matrices A and B, both of size 4x4. multiply the first column of A with all the other columns of B with:

bsxfun(@times, A(:,1),B)

，但我想对A的每一列重复此操作，即即将A的所有列乘以B的所有列.如何使用bsxfun(没有循环或repmat)来做到这一点?

but what I want to do is to repeat this operation for each column of A, i.e multiply all columns of A by all columns of B. How can I do this with bsxfun (without loops or repmat)?

推荐答案

是，通过

Yes, by permuting the dimensions of one of the matrices to make it a 4x1x4 array:

permute(bsxfun(@times, A, permute(B, [1 3 2])), [1 3 2])

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