Matlab中的有序随机数 [英] Ordered random numbers in Matlab

问题描述

我正在尝试使用Matlab的randperm并调用randperm = 5来生成1到5之间的随机数.

I am trying to generate random numbers between 1 and 5 using Matlab's randperm and calling randperm = 5.

每次给我一个不同的数组，例如:

Each time this gives me a different array let's say for example:

x = randperm(5)
x = [3 2 4 1 5]

我需要对向量进行排列，以使4和5总是彼此相邻，而2总是在1和3之间...例如[3 2 1 4 5]或[4 5 1 2 3].

I need the vector to be arranged such that 4 and 5 are always next to each other and 2 is always between 1 and 3... so for e.g. [3 2 1 4 5] or [4 5 1 2 3].

所以从本质上讲，我有两个长度不相等的块"-1 2 3和4 5.块的顺序不是很重要，只是4& ;; 5个在一起，2个在1到3之间.

So essentially I have two "blocks" of unequal length - 1 2 3 and 4 5. The order of the blocks is not so important, just that 4 & 5 end up together and 2 in between 1 and 3.

我基本上只能有4种可能的组合:

I can basically only have 4 possible combinations:

[1 2 3 4 5]

[3 2 1 4 5]

[4 5 1 2 3]

[4 5 3 2 1]

有人知道我该怎么做吗?

Does anyone know how I can do this?

谢谢

推荐答案

您可以生成每个块并对其进行随机排序，然后将它们设置为单元格数组的成员，然后对单元格进行重新排序，最后将单元格数组转换为向量

You can generate each block and shuffle each one then and set them as members of a cell array and shuffle the cell array and finally convert the cell array to a vector.

b45=[4 5];                                        % block 1
b13=[1 3];                                        % block 2
r45 = randperm(2);                                % indices for shuffling block 1
r13 = randperm(2);                                % indices for shuffling block 2
r15 = randperm(2);                                % indices for shuffling the cell
blocks = {b45(r45) [b13(r13(1)) 2 b13(r13(2))]};  % shuffle each block and set them a members of a cell array
result = [blocks{r15}]                            % shuffle the cell and convert to a vector

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