等效于python中的csaps和ppval [英] Equivalent of csaps and ppval in python

问题描述

我正在尝试使用 numpy 和 scipy 将一些 matlab 代码转换为python.

I'm trying to convert some matlab code into python using numpy and scipy.

这是matlab代码:

Here is the matlab code :

pp=csaps(Data(:,1),Data(:,2),0.9999);
new_data= ppval(pp,Data(:,1));

在python中，我从SmoothSpline函数替换了csaps ="nofollow"> pywafo 库.但是我找不到替换ppval的任何函数.

In python, I replace csaps by the SmoothSpline function from pywafo library. But I'm not able to find any function to replace ppval.

这是当前的python代码:

Here is the current python code:

pp = SmoothSpline(Data[0], Data[1], 0.9999)
new_data = pp(Data[0]) # should use ppval?

有什么主意吗?预先感谢！

Any idea? Thanks in advance!

推荐答案

我没有使用pywafo库中的SmoothSpline，但我使用了Scipy中的UnivariateSpline. 这是来自 Scipy样条

I havent used SmoothSpline from pywafo library but i have used UnivariateSpline from Scipy. Here is a minimal working example from Scipy Spline

from scipy.interpolate import UnivariateSpline
x = np.linspace(0, 10, 70)
y = np.sin(x)
spl = UnivariateSpline(x, y, k=4, s=0)

您可以按如下方式获得分段多项式函数MATLAB"ppval"的值

you can obtain the value of the piecewise polynomial function MATLAB "ppval" as follows

spl(Data[0])

正如您在上文中正确指出的那样

as you have rightly stated above

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