截断数组 [英] Truncating an array

问题描述

我的代码的简化版本如下:

A simplified version of my code is as follows:

A = linspace(0,10,100);
threshold = 6.0;

我想将向量A截断到低于阈值的值.

I'd like to truncate the vector A at values below the threshold value.

假设A中的值总是递增，那么如何才能整齐而有效地做到这一点?

Assuming that the values in A are always ascending, how can I do this neatly and efficiently?

当前，我唯一想到的方法是引入一个for循环并逐个检查每个元素，如果它的值大于阈值，然后将该值分配给新数组.像这样:

Currently the only method I can think of is to introduce a for-loop and examine each element, one after another and if it has a value above the threshold, and then to allocate this value to a new array. Something like this:

    k=1;
    for i = 1:numel(A)
        if A(i) < threshold
        elseif A(i) >= threshold
            Atrunc(k,1) = A(i);
            k=k+1;
        end
    end 

但是，这对我来说似乎不是很好"，有人可以提供更优化的代码吗??

However this doesn't seem very 'nice' to me, can anybody offer more optimized code...?

推荐答案

使用逻辑索引

A = A(A < threshold);

或

A = A(A >= threshold);

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