散点图中的各个alpha值 [英] Individual alpha values in scatter plot

问题描述

我想知道是否可以使用Matplotlib的scatter函数为每个点绘制单独的alpha值.我需要绘制一组点，每个点都有其alpha值.

I'm wondering if it is possible to have individual alpha values for each point to be plotted using the scatter function of Matplotlib. I need to plot a set of points, each one with its alpha value.

例如，我有这段代码可以绘制一些点

For example, I have this code to plot some points

def plot_singularities(points_x, p, alpha_point, file_path):
    plt.figure()
    plt.scatter(points_x, points_y, alpha=alpha_point)
    plt.savefig(file_path + '.png', dpi=100)
    plt.close()

我的所有points_x，points_y和alpha_point都具有n个值.但是，我无法将数组分配给scatter()中的alpha参数.如何为每个点设置不同的alpha值?我可以逐个循环并绘制每个特定的alpha值，但这似乎不是一个好方法.

All my points_x, points_y and alpha_point have n values. However, I can't assign an array to the alpha parameter in scatter(). How can I have a different alpha value for each point? I can loop and plot point by point with each specific alpha value, but this doesn't seem like a good approach.

推荐答案

tcaswell的建议是正确的，您可以这样做:

tcaswell's suggestion is correct, you can do it like this:

import numpy as np
import matplotlib.pylab as plt

x = np.arange(10)
y = np.arange(10)

alphas = np.linspace(0.1, 1, 10)
rgba_colors = np.zeros((10,4))
# for red the first column needs to be one
rgba_colors[:,0] = 1.0
# the fourth column needs to be your alphas
rgba_colors[:, 3] = alphas

plt.scatter(x, y, color=rgba_colors)
plt.show()

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