Matplotlib，图例，带有一个标签的多个不同标记 [英] Matplotlib, legend with multiple different markers with one label

问题描述

这是情况的简化图:

我希望每个数据点标记都具有一个单独的标签，而我希望能够为一组不同的标记使用一个标签.我希望能够有一个像这样的传说:

Instead of have each data point marker have a separate label, I want to be able to have one label for a set of different markers. I would like to be able to have a legend like:

<triangle> <square> <hexagon> <diamond> <circle> Shotcrete strength data points
<green line> 10 minute strength
<blue line> 60 minute strength
<yellow line> 1 day strength
<orange line> 7 day strength
<red line> 28 day strength

我想这样做是因为在最后的绘图中，我将拥有三组数据点，并且显示18个(3组* 6点/组)标记/标签组合会很杂乱.

I want to do this because in the final plot I will have three sets of data points and showing 18 (3 sets * 6 points/set) marker/label combinations will be messy.

我正在将Matplotlib与Python 2.7结合使用.

I am using Matplotlib with Python 2.7.

推荐答案

注意:保留此答案作为正确答案的指南-但这不能解决所陈述的问题.有关matplotlib不支持补丁集合的问题，请参见下面的编辑.

Note: This answer is kept up as a guide to the correct answer - but it does not solve the stated problem. Please see the edit below for the problem of Patch collections not being support in matplotlib.

如果要完全自定义，一种解决方法是使用所谓的代理艺术家:

One way to go about this, if you want complete customization is to use a so-called Proxy Artist:

from pylab import *

p1 = Rectangle((0, 0), 1, 1, fc="r")
p2 = Circle((0, 0), fc="b")
p3 = plot([10,20],'g--')
legend([p1,p2,p3], ["Red Rectangle","Blue Circle","Green-dash"])

show()

在这里，您可以精确地指定 您想要图例的外观，甚至可以使用非标准的绘图形状(补丁).

Here you can specify exactly what you'd like the legend to look like, and even use non-standard plot shapes (patches).

编辑:这种方法有些困难，

There is some difficulty with this method, matplotlib only supports these Artists in a legend without tweaking. For matplotlib v1.0 and earlier, the supported artists are as follows.

Line2D
Patch
LineCollection
RegularPolyCollection
CircleCollection

您的多个分散点请求将通过补丁集合，上面不支持.从理论上讲，对于v1.1，这是可行的，但我不知道如何做到.

Your request of multiple scatter points would be done with a Patch Collection, which is not supported above. In theory with v1.1, this is possible but I do not see how.

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