matplotlib图集x_ticks [英] matplotlib plot set x_ticks

问题描述

如何将索引1,2,3 .... n的x_axis标签设置为不同的内容.

How would I set the x_axis labels at the indices 1,2,3....n to be something different.

lam_beta = [(lam1,beta1),(lam1,beta2),(lam1,beta3),....(lam_n,beta_n)]
chunks = [chunk1,chunk2,...chunk_n]
ht_values_per_chunk = {chunk1:[val1,val2,...],chunk2:[val1,val2,val3,.....]...}
color='rgbycmk'
     j=0
     for chunk in chunks:
        plt.plot([hr_values_per_chunk[chunk][i] for i,item in enumerate(lam_beta)],[i for i,item in enumerate(lam_beta)],color=j%len(color))
        j+=1

     plt.set_xticks([i for i,item in enumerate(lam_beta)])
     plt.set_xticklabels([item for item in lam_beta],rotation='vertical')
     plt.show()

错误:

AttributeError:模块"对象没有属性"set_xticks"

AttributeError: 'module' object has no attribute 'set_xticks'

在这里，我无法将lambda_beta元组的值设置为x轴上每个刻度的值，因为它说plt没有这种方法.我将如何实现这一目标?我使用xticks是因为这是我在matplotlib中生成直方图时所做的.任何帮助，将不胜感激.提前致谢！

Here I am unable to set the values of the lambda_beta tuple to be the values of each of the ticks on the x-axis as it say plt has no such method. How would I be able to achieve this for plt? I used xticks because this is how I had done it while generating a histogram in matplotlib. Any help would be appreciated. Thanks in advance!

推荐答案

set_xticks 和 set_xticklabels 是轴方法，而不是函数在plt模块名称空间中.这就是错误消息'module' object has no attribute 'set_xticks'的含义.

set_xticks and set_xticklabels are axes methods, not functions in the plt module namespace. This is the meaning of the error message, 'module' object has no attribute 'set_xticks'.

此外

[i for i,item in enumerate(lam_beta)]

可以简化为

range(len(lam_beta))

和

[item for item in lam_beta]

可以简化为

lam_beta

方便使用axes的方法是致电 plt.subplots :

A convenient way to get your hands on the axes is to call plt.subplots:

所以:

fig, ax = plt.subplots()
...
ax.set_xticks(range(len(lam_beta)))
ax.set_xticklabels(lam_beta, rotation='vertical')

ax是Axes对象.调用Axes方法是使用matplotlib的面向对象方法.

ax is an Axes object. Calling Axes methods is the object-oriented approach to using matplotlib.

或者，您可以通过调用 plt.xticks .如果我们定义

Alternatively, you could use the Matlab-style pylab interface by calling plt.xticks. If we define

loc = range(len(lam_beta))
labels = lam_beta

然后

plt.xticks(loc, labels, rotation='vertical')

等同于

fig, ax = plt.subplots()
ax.set_xticks(loc)
ax.set_xticklabels(labels, rotation='vertical')

plt.xticks将刻度位置和标签设置为当前轴.

plt.xticks sets the tick locations and labels to the current axes.

列表理解

[hr_values_per_chunk[chunk][i] for i,item in enumerate(lam_beta)]

可以简化为

hr_values_per_chunk[chunk][:len(lam_beta)]

并且您可以避免使用ax.plot的调用设置color参数. ="noreferrer"> ax.set_color_cycle :

And you could eschew setting the color parameter for each call to ax.plot by using ax.set_color_cycle:

import matplotlib.pyplot as plt

fig, ax = plt.subplots()
lam_beta = [(lam1,beta1),(lam1,beta2),(lam1,beta3),....(lam_n,beta_n)]
chunks = [chunk1,chunk2,...chunk_n]
ht_values_per_chunk = {chunk1:[val1,val2,...],chunk2:[val1,val2,val3,.....]...}
color='rgbycmk'
ax.set_color_cycle(colors)

for chunk in chunks:
    vals = hr_values_per_chunk[chunk][:len(lam_beta)]
    ax.plot(vals, range(len(lam_beta)))

ax.set_xticks(range(len(lam_beta)))
ax.set_xticklabels(lam_beta, rotation='vertical')
plt.show()

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