R:获取矩阵中最小元素的行和列名，但最小！= 0 [英] R: Get the row and column name of the minimum element of a matrix but with minimum != 0

问题描述

我有一个矩阵，其中包含很多零和正数值. 我想获取元素所在的行号和列号 矩阵的最小NONZERO值.

I've got a matrix with a lot of zeros and with positive numerical values. I want to get the row and column number for which the element is the minimal NONZERO value of the matrix.

我没有发现min()有额外的选项来排除零，所以我怎么能 处理这个?

I don't find that min() has extra options to exclude zero, so how can I handle this?

推荐答案

似乎答案可能更短，但是您可以将NA替换为零，并使用na.rm = T

Seems like there could be a shorter answer but u can replace the zeros with NA and use na.rm=T

test = matrix(c(0:9,0:9),nrow =4,ncol=5)
test[which(test==0)] = NA
minValue = min(test,na.rm=T) 
rows = which(apply(test,1,min,na.rm=T)==minValue)
cols = which(apply(test,2,min,na.rm=T)==minValue)

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