查找矩阵的最大值和最小值 [英] Find maximum and minimum value of a matrix
本文介绍了查找矩阵的最大值和最小值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我将这段代码写在python 3中:
I have this code wrote in python 3:
matrix = []
loop = True
while loop:
line = input()
if not line:
loop = False
values = line.split()
row = [int(value) for value in values]
matrix.append(row)
print('\n'.join([' '.join(map(str, row)) for row in matrix]))
print('matrix saved')
返回矩阵的示例为[[1,2,4],[8,9,0]].我想知道如何找到矩阵的最大值和最小值?我尝试了python的max(matrix)和min(matrix)内置函数,但是它不起作用.
an example of returned matrix would be [[1,2,4],[8,9,0]].Im wondering of how I could find the maximum and minimum value of a matrix? I tried the max(matrix) and min(matrix) built-in function of python but it doesnt work.
感谢您的帮助!
推荐答案
在删除列表列表后,使用内置函数max()
和min()
:
Use the built-in functions max()
and min()
after stripping the list of lists:
matrix = [[1, 2, 4], [8, 9, 0]]
dup = []
for k in matrix:
for i in k:
dup.append(i)
print (max(dup), min(dup))
运行方式为:
>>> matrix = [[1, 2, 4], [8, 9, 0]]
>>> dup = []
>>> for k in matrix:
... for i in k:
... dup.append(i)
...
>>> print (max(dup), min(dup))
(9, 0)
>>>
这篇关于查找矩阵的最大值和最小值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文