用它们的逆矩阵替换矩阵的所有元素 [英] Replace all elements of a matrix by their inverses

问题描述

我有一个简单的问题，我不知道如何解决.

I've got a simple problem and I can't figure out how to solve it.

这是一个矩阵:A = np.array([[1,0,3],[0,7,9],[0,0,8]]).

我想找到一种快速的方法，用它们的逆值替换矩阵中的所有元素，当然不包括零元素.

I want to find a quick way to replace all elements of this matrix by their inverses, excluding of course the zero elements.

由于Stackoverflow的搜索引擎，我知道如何用条件用给定值替换元素.相反，我不知道如何根据以前的元素(例如，平方元素，逆元素等)用新元素替换元素

I know, thanks to the search engine of Stackoverflow, how to replace an element by a given value with a condition. On the contrary, I do not figure out how to replace elements by new elements depending on the previous ones (e.g. squared elements, inverses, etc.)

推荐答案

还有关于Antti Haapala答案的注释，(对不起，我无法发表评论) 如果您想保留0，可以使用

And just a note on Antti Haapala's answer, (Sorry, I can't comment yet) if you wanted to keep the 0's, you could use

B=1./A #I use the 1. to make sure it uses floats
B[B==np.inf]=0

这篇关于用它们的逆矩阵替换矩阵的所有元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！