如何使用R以百分比显示两列的相似性? [英] How to show a similarity of two columns in percentage using R?

问题描述

我有一个简单的问题要存入其中！ 我有两个data.frame，我想比较它们并以百分比显示它们的相似性，但是我不知道怎么做！

I have a simple question which I stock in it! I have two data.frames and I want to compare them and show their similarity in percentage but I do not know how!

这是一个简单的例子:

   a <- as.matrix(rbinom(10,1,1/2))
    b <- as.matrix(rbinom(10,1,1/2))

    > a
              [,1]
         [1,]    1
         [2,]    0
         [3,]    1
         [4,]    0
         [5,]    1
         [6,]    0
         [7,]    1
         [8,]    1
         [9,]    1
        [10,]    0

   > b
         [,1]
     [1,]    1
     [2,]    0
     [3,]    1
     [4,]    1
     [5,]    0
     [6,]    0
     [7,]    0
     [8,]    0
     [9,]    1
    [10,]    0

我知道该表显示了差异/相似性

I know that table shows the differences/similarities

   > table(a,b)
       b
    a   0 1
      0 3 1
      1 3 3

但是如何计算百分比呢?例如显示a中的值是否与b相似X％?

But how can I calculate the percentage for it? for example to show values in a are X% similar to b?

推荐答案

感谢您的评论，但我的意思是要显示两列之间的总体相似性，在这里，如果您查看这些矩阵，它们具有6个相似的变量:

Thanks for your comments, but what I meant was to show the over all similarity between two columns which in here if you look at these matrices they have 6 variables similar:

，最终的相似度百分比为: 6/10 ==> 60％

and the final similarity in percentage would be: 6/10 ==> 60%

我找到了解决方法:

colSums(a==b)/length(a)*100
[1] 60

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