如何生成两个随机数开出4？ [英] How to generate two random numbers out of 4?

问题描述

我需要两个随机数选自1，2，3和4，但它们不能是相同的，我需要它们在两个不同的变量。

I need two random numbers out of 1, 2, 3 and 4, but they cannot be the same and I need them in two different variables.

所以，像 rnd1 = 1; 和 RND2 = 3; 。

我试图生成它们的经典风格： INT RND =新的随机（）nextInt（3）+ 1; 。而对于另外一个同样的方式，但如何保证它们不匹配？那怎么办？

I tried to generate them classic style: int rnd = new Random().nextInt(3) + 1;. And for the other one the same way, but how to ensure that they don't match? How to do that?

推荐答案

而不是实施随机性和唯一性你自己，你可以简单地填充列表的允许号码，<一个href=\"http://developer.android.com/reference/java/util/Collections.html#shuffle%28java.util.List%3C?%3E%29\">shuffle它，并采取前两个项目：

Rather than implementing the randomness and unicity yourself, you could simply populate a list with the allowed numbers, shuffle it and take the first two entries:

List<Integer> list = Arrays.asList(1, 2, 3, 4);
Collections.shuffle(list);
rnd1 = list.get(0);
rnd2 = list.get(1);

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