Spring应用程序未在Tomcat中映射 [英] Spring application not mapping in Tomcat
问题描述
我相信我在某处设置有问题，但是由于尝试了多个教程和解决方案，我无法弄清楚哪里( stackoverlow问题，
I'm convinced I have something setup wrong somewhere but I can't figure out where as I have tried following multiple tutorials and solution (viralpatel.net, stackoverlow question, another stackoverflow question) but I cannot deploy a simple HelloWorld Spring MVC to tomcat.
我已经在多台计算机(Windows 7和OS x 10.7)上尝试了多个教程，但最终遇到了相同的问题.我关注的主要教程是 mykong Spring 3 MVC你好世界示例，我什至尝试下载提供的源代码，但仍然无法使它正常工作(变得非常令人沮丧).
I have tried multiple tutorials on multiple machines (windows 7 and os x 10.7), and I end up with the same issue. The main tutorial I was following was the mykong Spring 3 MVC hello World example , I even tried to download the supplied source code and still cannot get it to work ( it is becoming very Frustrating).
我的服务器是apache-tomcat-6.0.36，它似乎可以正确部署到tomcat，但是我无法访问任何页面(我什至尝试仅将纯HTML页面放在根目录中，但仍然会出现404错误)但是，如果我在webapps目录中手动创建一个新文件夹"test"并在其中放置index.html，则localhost:8081/test/可以正常工作.我也尝试过Tomcat 7，但没有任何区别.
My Server is apache-tomcat-6.0.36 and it appears to deploy to tomcat correctly but I cannot get to any pages (I have even tried just putting a plain html page in the root but that still gives a 404 error) but if I manually create a new folder "test" in the webapps directory and put a index.html in there then localhost:8081/test/ works fine. I have also tried Tomcat 7 but made no difference.
这是我的项目结构:
这是我的web.xml:
this is my web.xml:
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring Web MVC Application</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
这是我的mvc-dispatcher-servlet.xml
This is my mvc-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.mkyong.common.controller" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
这是控制器:
package com.mkyong.common.controller;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
@RequestMapping("/welcome")
public class HelloController {
@RequestMapping(method = RequestMethod.GET)
public String printWelcome(ModelMap model) {
model.addAttribute("message", "Spring 3 MVC Hello World");
return "hello";
}
}
hello.jsp:
hello.jsp:
<html>
<body>
<h1>Message : ${message}</h1>
</body>
</html>
解决方案
正如duffymo所指出的，我的应用程序部署不正确，因此我右键单击了eclipse中的项目，并将其作为"WAR"文件导出到我的tomcat webapps目录中，并且现在可以正常使用
Solution
As duffymo pointed out, my application wasn't being deployed correctly, So I right clicked on the project in eclipse and exported as a "WAR" file to my tomcat webapps directory and it is working now
推荐答案
您没有正确打包和部署应用.
You are not packaging and deploying your app correctly.
我建议您将应用程序打包到适当的WAR文件中，并将其放在/webapps文件夹中，然后启动Tomcat.
I'd recommend that you package your app into a proper WAR file, put that in the /webapps folder, and start Tomcat.
如果该程序包名为foo.war，则您的URL将为:
If the package is named foo.war, your URL will be:
http://localhost:8080/foo/welcome
如果您的回答是我做到了，但没有成功"，答案是您仍然做错了."
If your response is "I did that and it didn't work", the answer is "You still did it wrong."
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