用Maven生成类路径文件 [英] Generating classpath file with Maven

问题描述

我想从pom.xml依赖项生成一个类路径文件.我需要它，因此在测试过程中，我具有所有依赖项的类路径(以后将它们打包成一个包)

I'd like to generate a classpath file from pom.xml dependencies. I need it so during tests I have the classpath of all dependencies (that are later packaged into a bundle)

maven-dependency-plugin不适合我，原因有两个:

maven-dependency-plugin does not suit me for two reasons:

• 它会生成存储库中文件的路径，因此要使用其他模块，它们首先需要为其运行install阶段(我想使用类似/some/root/othermodule/target/classes的路径)
• 它不包含工件自身的路径(target/classes)，这意味着我需要稍后在代码中添加它，这很尴尬

• it generates paths to files in the repository, so to use other modules they first need to run install phase for them (I'd like to have paths like /some/root/othermodule/target/classes)
• it doesn't include the artifact's own path (target/classes), which means I need to add it later in code, which is awkward

所以我正在寻找另一个插件(或如何正确运行maven-dependency-plugin)

So I'm looking for another plugin (or how to properly run maven-dependency-plugin)

推荐答案

我最终使用了GMaven:

I ended up using GMaven:

        <plugin>
            <groupId>org.codehaus.groovy.maven</groupId>
            <artifactId>gmaven-plugin</artifactId>
            <executions>
                <execution>
                    <phase>generate-resources</phase>
                    <goals>
                        <goal>execute</goal>
                    </goals>
                    <configuration>
                        <source>
                            def all = project.runtimeArtifacts.collect{
                                def aid = "${it.groupId}:${it.artifactId}:${it.version}"
                                def p = project.projectReferences[aid]
                                p?.build?.outputDirectory ?: it.file.path
                            } + project.build.outputDirectory
                            def file = new File(project.build.directory, ".classpath")
                            file.write(all.join(File.pathSeparator))
                        </source>
                    </configuration>
                </execution>
            </executions>
        </plugin>

代码有点复杂，因为我想尽可能地找到目标/类的路径.如果这不是必需的，则可以执行以下操作:

The code is a bit complex since I wanted paths to target/classes when possible. If this is not required, one can do :

file.write(project.runtimeClasspathElements.join(File.pathSeparator))

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