Python查找列表的最小最大值和平均值(数组) [英] Python find min max and average of a list (array)

问题描述

我很难找出如何从列表中查找分钟 例如

I am having hard time to figure out how to find min from a list for example

somelist = [1,12,2,53,23,6,17]

如何通过定义(def)函数来查找此列表的最小值和最大值

how can I find min and max of this list with defining (def) a function

我不想使用内置功能min

推荐答案

from __future__ import division

somelist =  [1,12,2,53,23,6,17] 
max_value = max(somelist)
min_value = min(somelist)
avg_value = 0 if len(somelist) == 0 else sum(somelist)/len(somelist)

如果要手动查找最小值作为函数:

If you want to manually find the minimum as a function:

somelist =  [1,12,2,53,23,6,17] 

def my_min_function(somelist):
    min_value = None
    for value in somelist:
        if not min_value:
            min_value = value
        elif value < min_value:
            min_value = value
    return min_value

Python 3.4引入了 statistics 软件包，该软件包提供了以及其他统计信息:

Python 3.4 introduced the statistics package, which provides mean and additional stats:

from statistics import mean, median

somelist =  [1,12,2,53,23,6,17]
avg_value = mean(somelist)
median_value = median(somelist)

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