是否有一个numpy max min函数? [英] Is there a numpy max min function?
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问题描述
是否有一个numpy函数为给定的numpy数组提供最大值-最小值,即numpy.max(a)-numpy.min(a)?
Is there a numpy function that gives for a given numpy array its maximum - minimum value, i.e. numpy.max(a) - numpy.min(a) ?
例如
numpy.xxx([4,3,2, 6] = 4 since max = 6, min = 2, 6 - 4 = 2)
原因:由于max和min会导致数组迭代次数增加两倍(在我的情况下为750万个或更多),因此性能提高.
Reason: performance increase since max and min would cause twice the iteration of the array (which is in my case 7.5 million or more numbers).
推荐答案
Indeed there is such a function -- it's called numpy.ptp()
for "peak to peak".
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