而插座进行读/写操作过于频繁应用程序无响应 [英] Application not responding while performing a read/write operation on socket too frequently
问题描述
在我的应用我有一个用于读取状态12位的字节数组。写这阵之后我得到不同的按钮的状态。在此基础上的反应，我是我的按钮设置为ON | OFF。我这样做的任务repeatedly.if我设置间隔时间过少即100毫秒和pressing这些按钮过于频繁那么我的应用程序停止响应。
In my application i have byte array of 12 digit which is used to read the status. After writing this array i am getting the status of different buttons. Based on this response i am setting up my buttons to ON|OFF. i am doing this task repeatedly.if i set this interval time too less i.e 100ms and pressing those buttons too frequently then my application is stops to respond.
下面是code片段。
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main_activity);
getSharedSettings();
fanDimmer1=(ToggleButton)findViewById(R.id.button_fan1);
fanDimmer2=(ToggleButton)findViewById(R.id.button_fan2);
dimmerLight1=(ToggleButton)findViewById(R.id.button_light1);
dimmerLight2=(ToggleButton)findViewById(R.id.button_light2);
fanDimmer1.setOnClickListener(this);
fanDimmer2.setOnClickListener(this);
dimmerLight1.setOnClickListener(this);
dimmerLight2.setOnClickListener(this);
if(ip.equals("") || port.equals(""))
{
new AlertDialog.Builder(MainActivity.this)
.setTitle("Warning !")
.setMessage("Please set IP and PORT first")
.setIcon(android.R.drawable.ic_dialog_alert)
.setNeutralButton("ok", null)
.show();
}
else
{
new Thread(new Runnable()
{
@Override
public void run()
{
Log.v(TAG, "openconnection");
openConnection();
}
}).start();
m_handler = new Handler();
startRepeatingTask();
}
}
public void openConnection()
{
// TODO Auto-generated method stub
try
{
s = new Socket(ip, Integer.parseInt(port));
i = s.getInputStream();
iD = new DataInputStream(i);
o = s.getOutputStream();
oD = new DataOutputStream(o);
Log.v(TAG, "openconnection 2");
}
catch (UnknownHostException e) {
// TODO: handle exception
Log.v("UnknowHostException :::::", "In Catch Block");
e.printStackTrace();
}
catch (IOException e) {
// TODO: handle exception
Log.v("IOException :::::", "In Catch Block");
e.printStackTrace();
}
}
Runnable m_statusChecker = new Runnable()
{
@Override
public void run()
{
updateStatus();
m_handler.postDelayed(m_statusChecker,100);
}
private void updateStatus()
{
// TODO Auto-generated method stub
Log.v("test", "1");
try {
byte[] data1 = new byte[1024], packet1 =
{
(byte) 0x00,(byte) 0x00,(byte) 0x00,
(byte) 0x00,(byte) 0x00,(byte) 0x06,
(byte) 0x01,(byte) 0x01,(byte) 0x00,
(byte) 0x00,(byte) 0x00,(byte) 0x19
};
o.write(packet1);
i.read(data1, 0, 1024);
byte_to_hex = ConversionMethods.bytesToHex(data1).substring(18, 26);
char[] arr = byte_to_hex.toCharArray();
for (int i = 0; i < arr.length - 1; i += 2)
{
char temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
swapped_result=new String(arr);
result = ConversionMethods.hexStringToNBitBinary(swapped_result, 32);
int counter = 0;
for( int i=0; i<result.length(); i++ )
{
if( result.charAt(i) == '1' )
{
counter++;
}
}
status=Integer.toString(counter);
txt_status.setText(status);
Log.v(TAG, "status is ::"+status);
char[] c=result.toCharArray();
int count=0;
for (int i=0;i<result.length();i++)
{
count++;
char j=c[i];
//Log.v(TAG, count+"::"+j);
if(count==1)
toggleButton=dimmerLight1;
else if(count==2)
toggleButton=fanDimmer2;
else if(count==3)
toggleButton=fanDimmer1;
else if(count==4)
Log.v(TAG, "Count 4 is 0");
if(j=='1')
toggleButton.setChecked(true);
else
toggleButton.setChecked(false);
}
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
};
void startRepeatingTask() {
m_statusChecker.run();
}
void stopRepeatingTask() {
m_handler.removeCallbacks(m_statusChecker);
}
和按钮点击我这样做：
@Override
public void onClick(View v)
{
if(v.equals(fanDimmer1))
{
if (fanDimmer1.isChecked())
{
Toast.makeText(MainActivity.this, "Fan 1 is ON", Toast.LENGTH_SHORT).show();
setByteArray((byte) 0x01, (byte) 0xff);
} else
{
Toast.makeText(MainActivity.this, "Fan 1 is OFF", Toast.LENGTH_SHORT).show();
setByteArray((byte) 0x01, (byte) 0x00);
}
}
}
这里是 setByteArray（）方法
我有24个这种类型的按钮。
here is setByteArray() method i have 24 this type of buttons.
任何意见和建议，将AP preciated。结果
谢谢
Any advice and suggestion will be appreciated.
Thanks
推荐答案
您在呼唤 startRepeatingTask（）从你的主线程：
You are calling startRepeatingTask() from your main thread:
void startRepeatingTask() {
m_statusChecker.run();
}
这意味着你将statusChecker在主线程中运行了。
This means that your statusChecker will runs in the main thread too.
-
做的第一件事就是更新updateStatus方法的code和使用
mHandler后唯一的用户界面更新code到主UI线程
The first thing to do is to update the code of your updateStatus method and use
mHandlerto post ONLY ui-update code to the main UI-thread
接下来，您必须在另一个线程运行statusChecker
Next you have to run the statusChecker in another thread
要做到这一点，你有（至少）两个选项：
To do it, you have (at least) two options :
-
[复杂的方式]执行自己的线程管理和写这样的事情在你的startRepeatingTask
[The complex way] Do your own thread management and write something like this in your startRepeatingTask
无效startRepeatingTask（）{
新的Thread（m_statusChecker）。开始（）;
}
适应stop方法（即使用一个显示器，一个无限循环和睡眠）
adapt the stop method (i.e. use a monitor, an infinite loop and a sleep)
[聪明的办法]看看定时器和 TimerTask的（和<一个href=\"http://stackoverflow.com/questions/2161750/android-controlling-a-task-with-timer-and-timertask\">this)从Android API和使用它们来实现你所需要的。
[The smart way] Take a look at Timer and TimerTask (and this) from the Android API and use them to implement what you need.
修改
专注于这个code：
for (int i=0;i<result.length();i++)
{
count++;
char j=c[i];
//Log.v(TAG, count+"::"+j);
if(count==1)
toggleButton=dimmerLight1;
else if(count==2)
toggleButton=fanDimmer2;
else if(count==3)
toggleButton=fanDimmer1;
else if(count==4)
Log.v(TAG, "Count 4 is 0");
if(j=='1')
toggleButton.setChecked(true);
else
toggleButton.setChecked(false);
}
这个循环的效果将是：
The effect of this loop will be:
- 迭代0（如果有的话）：dimmerLight1会被选中或取消选中
- 迭代1（如果有的话）：fanDimmer2会被选中或取消选中
- 迭代2（如果有的话）：fanDimmer1会被选中或取消选中
- 迭代3（如果有的话）：fanDimmer1会被选中或取消选中
- 迭代4（如果有的话）：fanDimmer1会被选中或取消选中
- 迭代5（如果有的话）：fanDimmer1会被选中或取消选中
- ...（fanDimmer1将是检查或取消选中，直到循环结束）
我是pretty确保这个你不需要的东西。 （除非result.size（）始终是3，但在任何其他情况：今年code会产生奇怪的事情）
I'm pretty sure this not what you need. (except if result.size() is always 3, but in any other situation: this code will produce weird things)
您可以做这样的事情：
//assuming buttons is a ToggleButton[32] populated with all your buttons in the correct order
for (int i=0;i<result.length();i++)
{
buttons[i].setChecked(c[i]=='1');
}
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