比较python中两个文件的md5哈希值 [英] Compare md5 hashes of two files in python

问题描述

我想比较两个文件的哈希值.但是无论文件是否不同，即使具有不同的哈希比较结果 True

I want to compare hashes of two files. But no matter if files are different or not, even with different hashes comparison results True

这是代码:

import hashlib

hasher1 = hashlib.md5()
afile1 = open('canvas.png', 'rb')
buf1 = afile1.read()
a = hasher1.update(buf1)
print(str(hasher1.hexdigest()))

hasher2 = hashlib.md5()
afile2 = open('img5.png', 'rb')
buf2 = afile2.read()
b = hasher2.update(buf2)
print(str(hasher2.hexdigest()))

print(str(a) == str(b))

输出:

614c9853a7f62c5b60d7d15bde80708f
76dc116b2c1b19b265db5e657846e649
True

Process finished with exit code 0

推荐答案

作为一般规则，Python方法遵循

As a general rule Python methods follow the principle of command-query separation -- so that methods that modify the object (i.e. commands) return None. This includes, for example, list.sort, and dict.update. It is also true of the hasher1.update method. So

a = hasher1.update(buf1)

将None分配给a.而是使用

hasher1.update(buf1)
a = hasher1.hexdigest()

，对于b同样.

import hashlib

digests = []
for filename in ['canvas.png', 'img5.png']:
    hasher = hashlib.md5()
    with open(filename, 'rb') as f:
        buf = f.read()
        hasher.update(buf)
        a = hasher.hexdigest()
        digests.append(a)
        print(a)

print(digests[0] == digests[1])

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