用NA计算列中位数 [英] Calculate column medians with NA's

问题描述

我试图计算R中各个列的中位数，然后用该列中的每个值减去中位数.我在这里面临的问题是我不想删除该列中的N/A，但只返回它们而不减去中位数即可.例如

I am trying to calculate the median of individual columns in R and then subtract the median value with every value in the column. The problem that I face here is I have N/A's in my column that I dont want to remove but just return them without subtracting the median. For example

ID <- c("A","B","C","D","E") 
Point_A <- c(1, NA, 3, NA, 5) 
Point_B <- c(NA, NA, 1, 3, 2)

df <- data.frame(ID,Point_A ,Point_B)

是否可以计算具有N/A的列的中位数?我的最终输出将是

Is it possible to calculate the median of a column having N/A's? My resulting output would be

+----+---------+---------+
| ID | Point_A | Point_B |
+----+---------+---------+
| A  | -2      | NA      |
| B  | NA      | NA      |
| C  | 0       | -1      |
| D  | NA      | 1       |
| E  | 2       | 0       |
+----+---------+---------+

推荐答案

另一个选择是

library(dplyr)
 df %>%
     mutate_each(funs(median=.-median(., na.rm=TRUE)), -ID)

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