广播里的活动接收器 [英] broadcast receiver inside activity

问题描述

嗨伙计我怎么能实现在与一些参数的int和string类型？

沿着接收来自服务的意图活动的广播接收器

更新：

我有这样的活动下：

 私人广播接收器ReceivefrmSERVICE =新的广播接收器（）{    @覆盖
    公共无效的onReceive（上下文的背景下，意图意图）{        Toast.makeText（背景下，IN DA广播电台，
                Toast.LENGTH_LONG）.show（）;    }   };
 

和我有这样的服务功能时，选中的按钮被选中时调用从另一个活动的事件下：

 公共无效switchSpeaker（INT小时，诠释分钟）{       Toast.makeText（Server.this，小时+，+最小值，Toast.LENGTH_LONG）.show（）;       意向意图=新意图（这一点，andRHOME.class）;
       //intent.putExtra(\"sendMessage\",\"1）;
        startActivity（意向）;
        / *的PendingIntent圆周率= PendingIntent.getService（Server.this，0，myIntent，0）;
        AlarmManager almmgr =（AlarmManager）getSystemService（ALARM_SERVICE）;
        日历CLDR = Calendar.getInstance（）;
        INT分1 = cldr.get（Calendar.MINUTE）;
        cldr.setTimeInMillis（System.currentTimeMillis的（））;
        cldr.add（Calendar.SECOND，30）;
        almmgr.set（AlarmManager.RTC_WAKEUP，cldr.getTimeInMillis（），PI）; * /
    }
 

但它的崩溃？ ，该怎么办？

解决方案

 广播接收器接收器=新的广播接收器（）{
    @覆盖
    公共无效的onReceive（上下文的背景下，意图意图）{
       //做你STU​​FF
    }
}IntentFilter的过滤器=新的IntentFilter（）;
 

在onResume：（所以你只能得到，而在前台）

  filter.addAction（/ *您希望收到* /动作）;
registerReceiver（接收器，过滤器）;
 

在的onPause（在尝试捕捉是修复在注销错误的情况下，它被称为两次）

  {尝试
    unregisterReceiver（接收机）;
}赶上（抛出：IllegalArgumentException五）{
    如果（e.getMessage（）。包含（接收未注册））{
        //忽略此异常。这正是需要
        Log.w（TAG，试图注销时，它没有注册reciver）;
    }其他{
        //意外，再次引发
        Ë扔掉;
    }
}
 

Hi folks how I can implement a Broadcast receiver in an activity that receives intent from a service along with some parameter's of int and string type?

UPDATE:

I have this under the Activity:

 private BroadcastReceiver ReceivefrmSERVICE = new BroadcastReceiver(){

    @Override
    public void onReceive(Context context, Intent intent) {

        Toast.makeText(context, "IN DA BroadCASTER",
                Toast.LENGTH_LONG).show();

    }

   };

and I have this under a function in the service that is called on a event from another activity when a checked button is checked:

 public void switchSpeaker(int hr, int min){

       Toast.makeText(Server.this, hr +" , " +min, Toast.LENGTH_LONG).show();

       Intent intent = new Intent(this, andRHOME.class);
       //intent.putExtra("sendMessage","1");
        startActivity(intent);
        /*PendingIntent pi = PendingIntent.getService(Server.this, 0, myIntent, 0);
        AlarmManager almmgr = (AlarmManager) getSystemService(ALARM_SERVICE);
        Calendar cldr = Calendar.getInstance();
        int min1 = cldr.get(Calendar.MINUTE);
        cldr.setTimeInMillis(System.currentTimeMillis());
        cldr.add(Calendar.SECOND, 30);
        almmgr.set(AlarmManager.RTC_WAKEUP, cldr.getTimeInMillis(), pi);*/
    }

But its crashing?? ,What to do?

解决方案

BroadcastReceiver receiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {         
       // DO YOUR STUFF
    }
}

IntentFilter filter = new IntentFilter();

in onResume: (so you receive only while in foreground)

filter.addAction(/* the action you want to receive */);
registerReceiver(receiver, filter);

in onPause: (the try catch is to fix a bug in unregister in case it is called twice)

try {
    unregisterReceiver(receiver);
} catch (IllegalArgumentException e) {
    if (e.getMessage().contains("Receiver not registered")) {
        // Ignore this exception. This is exactly what is desired
        Log.w(TAG,"Tried to unregister the reciver when it's not registered");
    } else {
        // unexpected, re-throw
        throw e;
    }
}

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