由初始化器列表初始化的数组存储在哪里? [英] Where is an array initialized by an initializer list stored?

问题描述

给出这段代码:

(void)someFunction(void) {
    int array[] = {1,2,3,4,5,6,7,8,9,10};
}

数组的值存储在哪里?

• 堆栈?
• 堆?
• 与这些字符串文字一起使用. (它叫做高频堆吗?)
• 还有其他地方吗?

我问是因为不确定这个问题:

I'm asking because I'm unsure regarding this question:

在Objective-c中创建整数数组

推荐答案

数组本身将位于堆栈中.该函数的入口处将有一些代码，用于将存储在全局/静态存储区中某些未命名数组中的值复制到堆栈上的本地数组中.带有初始值的未命名全局/静态数组可能与字符串文字位于相同的常规存储区中.

The array itself will be on the stack. There will be a bit of code on entry to the function that copies the values which are stored in some unnamed array in a global/static memory area into the local array on the stack. It's likely that the unnamed global/static array with the initial values is in the same general memory area as string literals.

但是请注意，该标准并不需要所有这些内容-但这几乎是任何编译器将其实现的方式.足够聪明的编译器可能会注意到这些值只是递增的整数值，并可能生成一个循环来初始化本地数组，

Note however, that none of this is required by the standard - but it's pretty much how any compiler will implement it. A smart enough compiler might notice that the values are simply incremented integer values and might gen up a loop to init the local array,

(此答案假定为C/C ++-我不知道Objective-C是否会更改其中的任何内容.)

(this answer assumes C/C++ - I don't know if Objective-C would change any of this).

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