内存扫描仪始终返回相同的结果 [英] Memory scanner always returning the same results

问题描述

使用此代码，我想扫描速度更快，但是扫描总是返回相同的地址.

With this code I guess the scan was faster, but the scan always return the SAME address.

E.G.:

00123456
00124567
00135478
00145893
00123456 //start repeat 
00124567
00135478
00145893
00123456 //start repeat 
00124567
00135478
00145893

这是我的程序:

procedure SCANBYTE(value: integer);
var
 lpflOldProtect: dword;
 s: size_t;
 mbi: MEMORY_BASIC_INFORMATION;
 SI: SYSTEM_INFO;
 lpStartAddress, lpStopAddress: dword;
 addr: dword;
 i: dword;
begin
 GetSystemInfo(si);
 lpStartAddress := dword(SI.lpMinimumApplicationAddress);
 lpStopAddress := dword(SI.lpMaximumApplicationAddress);
 for addr := lpStartAddress to lpStopAddress do begin
  S:= VirtualQuery(Pointer(addr), MBI, SizeOf(MEMORY_BASIC_INFORMATION));
  if (S=SizeOf(MEMORY_BASIC_INFORMATION)) and (MBI.State = MEM_COMMIT) and (MBI.Type_9 = MEM_PRIVATE) and (MBI.RegionSize>0) and (MBI.Protect = PAGE_READWRITE) then begin
   for i := dword(MBI.BaseAddress) to (dword(MBI.BaseAddress) + dword(MBI.RegionSize)) - 4096 do begin
     if value = PBYTE(i)^ then ListBox1.Items.Add(IntToHex(i,8));
   end;
  end;
 end;
end;

我猜问题出在最后一个FOR循环中:

I guess the problem is at the last FOR loop:

(...)
for i := dword(MBI.BaseAddress) to (dword(MBI.BaseAddress) + dword(MBI.RegionSize)) - 4096 do begin
(...)

但是我真的不知道. 我该如何解决?

But I really don't know.. How can I solve this?

推荐答案

您可以在从起始地址到结束地址的循环中运行代码.每次循环时，地址addr都会增加 1 . VirtualQuery提供有关整个页面的信息.页面中的所有地址都具有相同的基本地址. 文档告诉您，此值四舍五入向下到下一个页面边界."

You run your code in a loop from the start address to the end address. The address addr increases by 1 each time around the loop. VirtualQuery gives you information about entire pages. All the addresses in a page have the same base address. The documentation tells you, "This value is rounded down to the next page boundary."

仔细观察一下，您应该看到mbi.BaseAddress在外循环的4096次迭代中保持不变(假设4096是页面大小).因此，您要一遍又一遍地重新扫描相同的内存块. (这也可能会解释为什么您的代码运行缓慢.)

Look more closely, and you should see that mbi.BaseAddress remains the same for 4096 iterations of your outer loop (assuming 4096 is the page size). Thus, you're re-scanning the same block of memory over and over again. (That might also explain why your code is slow.)

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