PHP数据库驱动的多级菜单 [英] PHP Database driven Multilevel Menu

问题描述

我想构建一个数据库驱动的多级菜单，我从[ http://abhijitpal.in/]中获得了它[1] ，但是这里的问题是我不能只将class = "dropdown"放在顶部菜单<ul>中，它也同样适用于子菜单.我只是做了一点修改，但是我不知道如何使用递归函数.下面是代码，请查看是否可以提供帮助

I want to built a database driven multilevel menu I got it from [http://abhijitpal.in/][1] but the problem here is i can't put class = "dropdown" only to the top menus <ul>, it also get applies to the sub menus as well. I just modified a little but I don't know how to use recursive function. Below is the code, please see if you can help

<?php     /** Function to display Catelogue Menu */

//select all rows from the main_menu table
$q ="SELECT * FROM catelogue WHERE cat_visibility = '1'";    
$r = mysqli_query($dbc, $q);

//create a multidimensional array to hold a list of menu and parent menu
$menu = array(
    'menus' => array(),
    'parent_menus' => array()
);

//build the array lists with data from the menu table
while ($row = mysqli_fetch_assoc($r)) {
    //creates entry into menus array with current menu id ie. $menus['menus'][1]
    $menu['menus'][$row['cat_id']] = $row;
    //creates entry into parent_menus array. parent_menus array contains a list of all menus with children
    $menu['parent_menus'][$row['cat_parentid']][] = $row['cat_id'];
}

    // Create the main function to build milti-level menu. It is a recursive function.  
    function nav_catelogue($parent, $menu) {
    //$html = "";
    if (isset($menu['parent_menus'][$parent])) { ?>
<ul>
        <?php
        foreach ($menu['parent_menus'][$parent] as $menu_id) {
            if (!isset($menu['parent_menus'][$menu_id])) { ?>
                <li><a href="<?php echo $menu['menus'][$menu_id]['link']; ?>"><?php echo $menu['menus'][$menu_id]['cat_name']; ?></a></li>
  <?php }
            if (isset($menu['parent_menus'][$menu_id])) { ?>
        <li><a href="#"><?php echo $menu['menus'][$menu_id]['cat_name']; ?></a>
                        <?php echo nav_catelogue($menu_id, $menu); ?>
                    </li>
            <?php }
        } ?>
     </ul>
<?php }

} 
?>

我的数据库结构是

-----------------------------------------
| cat_id   | cat_name    | cat_parentid |
-----------------------------------------
|  1       |  Home       |  0           |
|  2       |  About      |  0           |
|  3       |  Contact    |  0           |
|  4       |  History    |  2           |
|  5       |  Services   |  2           |
-----------------------------------------

我想要的期望输出:

• 首页
• 关于
  • 历史
  • 服务
  • HOME
  • ABOUT
    • History
    • Services

    这是@Mave的最终代码

    This is the final code as per @Mave

    <?php     /** Function to display Catelogue Menu */
    
    //select all rows from the main_menu table
    $q ="SELECT * FROM catelogue WHERE cat_visibility = '1'";    
    $r = mysqli_query($dbc, $q);
    
    //create a multidimensional array to hold a list of menu and parent menu
    $menu = array(
        'menus' => array(),
        'parent_menus' => array()
    );
    
    //build the array lists with data from the menu table
    while ($row = mysqli_fetch_assoc($r)) {
        //creates entry into menus array with current menu id ie. $menus['menus'][1]
        $menu['menus'][$row['cat_id']] = $row;
        //creates entry into parent_menus array. parent_menus array contains a list of all menus with children
        $menu['parent_menus'][$row['cat_parentid']][] = $row['cat_id'];
    }
    
        // Create the main function to build milti-level menu. It is a recursive function.  
        function nav_catelogue($parent, $menu, $top = false) {
            if (isset($menu['parent_menus'][$parent])) {
                //this is short code for if($top === true) { //do true } else { //do false }
                echo $top ? '<ul class="dropdown">' : '<ul>';
                foreach ($menu['parent_menus'][$parent] as $menu_id) {
                    if (!isset($menu['parent_menus'][$menu_id])) {
                        echo '<li><a href="' . $menu['menus'][$menu_id]['link'] . '">' . $menu['menus'][$menu_id]['cat_name'] . '</a></li>';
                    }
                    if (isset($menu['parent_menus'][$menu_id])) {
                        echo '<li><a href="#">' . $menu['menus'][$menu_id]['cat_name'] . '</a>' . nav_catelogue($menu_id, $menu) . '</li>';
                    }
                }
                echo '</ul>';
            }
        }
    ?>
    

    推荐答案

    function nav_catelogue($parent, $menu, $top = false) {
        if (isset($menu['parent_menus'][$parent])) {
            //this is short code for if($top === true) { //do true } else { //do false }
            echo $top ? '<ul class="dropdown">' : '<ul>';
            foreach ($menu['parent_menus'][$parent] as $menu_id) {
                if (!isset($menu['parent_menus'][$menu_id])) {
                    echo '<li><a href="' . $menu['menus'][$menu_id]['link'] . '">' . $menu['menus'][$menu_id]['cat_name'] . '</a></li>';
                }
                if (isset($menu['parent_menus'][$menu_id])) {
                    echo '<li><a href="#">' . $menu['menus'][$menu_id]['cat_name'] . '</a>' . nav_catelogue($menu_id, $menu) . '</li>';
                }
            }
            echo '</ul>';
        }
    }
    

    首次调用nav_catelogue(当前代码中不存在)时，请使用nav_catelogue($menu_id, $menu, true);

    When you first call nav_catelogue (not present in your current code), call it with nav_catelogue($menu_id, $menu, true);

    这篇关于PHP数据库驱动的多级菜单的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！