菜单项单击隐藏弹出窗口 [英] Menu item click hides popup

问题描述

我的菜单中有带有复选框的项目列表:

I have list of items with checkboxes in my menu:

<menu xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    tools:context=".ListActivity">
    <group
        android:checkableBehavior="all"
        android:orderInCategory="1">
        <item
            android:id="@+id/all"
            android:checkable="true"
            android:checked="true"
            android:icon="@android:drawable/ic_menu_preferences"
            android:title="@string/category_all" />
        <item
            android:id="@+id/entertainment"
            android:checkable="true"
            android:checked="true"
            android:title="@string/category_1" />
        <item
            android:id="@+id/sport"
            android:checkable="true"
            android:checked="true"
            android:title="@string/category_2" />
        <item
            android:id="@+id/recreation"
            android:checkable="true"
            android:checked="true"
            android:title="@string/category_3" />
    </group>
</menu>

但是，如果我单击任何项​​目，则窗口关闭.我知道，它应该像这样工作.但是我需要保持此弹出窗口为打开状态.请帮助我！

but if I click on any item is, the window closes. I know, it should work like this. But I need keep this popup open. Please help me somebody!

推荐答案

尝试在onOptionsItemSelected方法中使用"return false". 希望它对您有用！

Try using "return false " in onOptionsItemSelected method . hope it will work for you !!

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