Mercurial可以在不获取书签的情况下进行拉动吗? [英] Can Mercurial pull without getting bookmarks?

问题描述

每次从存储库中提取数据时，我不仅会获得更改集，而且还会从该存储库中获得所有书签.在某些情况下，这很烦人.有没有没有书签就可以拉的方法?

Every time I pull from a repository I get not only the changesets but also all the bookmarks from that repository. In some situations this is quite annoying. Is there a way to pull without getting bookmarks?

(我实际上正在使用TortoiseHG，但是有关普通Mercurial命令行的信息也是有用的，并且值得赞赏.)

(I'm actually using TortoiseHG, but information about plain Mercurial command line is useful and appreciated as well.)

(背景:在TortoiseHG中，有很多书签很快就会混乱.在远程存储库中保留书签以备将来参考并不重要.但是在本地，我不需要或想要它们.因此，每次从远程存储库，我必须分别删除每个书签.这会很快变旧...)

(Background: In TortoiseHG having many bookmarks gets cluttered quickly. That doesn't matter in the remote repository where the bookmarks should remain for future reference. But locally I don't need or want them. So after each pull from the remote repository I have to delete each bookmark individually. This gets old fast...)

推荐答案

我不认为push会复制书签，那么为什么不转到远程存储库并从那里推送到您的存储库呢?

I don't think that push copies bookmarks, so why not go to the remote repository and from there push into yours?

或者，.hg/bookmarks只是一个文本文件，如果将其复制，拉出然后还原原始文件，会发生什么情况?

Alternatively, .hg/bookmarks is just a text file, what happens if you copy it, pull, and then restore the original?

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