当一个变量实际上是两列时，expand.grid [英] expand.grid when one variable is really two columns

问题描述

我有一个包含地区，县和年份的数据集.如果给定的地区/县组合发生在任何一年，我希望该组合发生在每年.下面是我想出的两种方法.第一种方法使用一个函数来创建地区，县和年份的组合，并且只需要六行代码.底部方法使用paste，expand.grid和strsplit的组合，更加复杂/复杂.

I have a data set with districts, counties and years. If a given district/county combination occurs in any year I want that combination to occur in every year. Below are two ways I have figured out to do this. The first approach uses a function to create combinations of district, county and year and only requires six lines of code. The bottom approach uses a combination of paste, expand.grid and strsplit and is much more complex/convoluted.

可能有比上述任何一种方法更有效的方法.例如，是否有一种方法可以使用expand.grid可能仅用1或2行代码即可实现地区/县/年的组合?

There are probably much more efficient methods than either above. For example, is there a way to use expand.grid that might achieve the district/county/year combinations perhaps with only 1 or 2 lines of code?

谢谢您的任何建议.我的职能部门可以胜任，但是这个问题对我来说是一个学习的机会.我更喜欢R.

Thank you for any advice. My function can do the job, but this question is a learning opportunity for me. I prefer base R.

这是示例数据集:

df.1 <- read.table(text = '
    state    district    county   year   apples
       AA          EC        A    1980     100
       AA          EC        B    1980      10
       AA          EC        C    1980     150
       AA           C        G    1980     200
       AA           C    other    1980      20
       AA           C        I    1980     250
       AA          WC        R    1980     300
       AA          WC        S    1980      30
       AA          WC     other   1980     350
       AA          EC        A    1999    1100
       AA          EC        D    1999     110
       AA          EC        E    1999    1150
       AA           C        H    1999    1200
       AA           C        I    1999     120
       AA           C        J    1999    1250
       AA          WC        R    1999    1300
       AA          WC    other    1999     130
       AA          WC        T    1999    1350
', header=TRUE, stringsAsFactors = FALSE)

这是预期的结果:

desired.result <- read.table(text = '
   state district county  year apples
      AA        C      G  1980    200
      AA        C      H  1980     NA
      AA        C      I  1980    250
      AA        C      J  1980     NA
      AA        C  other  1980     20
      AA       EC      A  1980    100
      AA       EC      B  1980     10
      AA       EC      C  1980    150
      AA       EC      D  1980     NA
      AA       EC      E  1980     NA
      AA       WC  other  1980    350
      AA       WC      R  1980    300
      AA       WC      S  1980     30
      AA       WC      T  1980     NA
      AA        C      G  1999     NA
      AA        C      H  1999   1200
      AA        C      I  1999    120
      AA        C      J  1999   1250
      AA        C  other  1999     NA
      AA       EC      A  1999   1100
      AA       EC      B  1999     NA
      AA       EC      C  1999     NA
      AA       EC      D  1999    110
      AA       EC      E  1999   1150
      AA       WC  other  1999    130
      AA       WC      R  1999   1300
      AA       WC      S  1999     NA
      AA       WC      T  1999   1350
', header=TRUE, stringsAsFactors = FALSE)

这是到目前为止我最简单的解决方案，它使用一个函数来表示每年的每个区/县组合:

Here is my most straight-forward solution so far, which uses a function to represent every district/county combination for each year:

my.unique.function <- function(year) {
     my.unique     <- data.frame(unique(df.1[, c('state', 'district', 'county')]), year)
     return(my.unique = my.unique)
}

years <- as.data.frame(unique(df.1[, 'year']))
my.unique.output <- apply(years, 1, function(x) {my.unique.function(x)})
my.unique.output2 <- do.call(rbind.data.frame, my.unique.output)

desired.result2 <- merge(df.1, my.unique.output2, by = c('state', 'year', 'district', 'county'), all=TRUE)

# compare output with a priori desired result
desired.result <- desired.result[order(desired.result$state, desired.result$year, desired.result$district, desired.result$county),]
all.equal(desired.result[,c(1,4,2,3,5)], desired.result2[,1:5])

这是我最初的更复杂的解决方案:

Here is my initial, much more complex solution:

# find unique combinations of district and county
my.unique     <- unique(df.1[, c('district', 'county')])

# paste district and county together
my.unique$x   <- apply( my.unique[ , c('district', 'county') ] , 1 , paste , collapse = "-" )

# represent each district/county combination for each year
expand.unique      <- expand.grid(my.unique$x, year = c(1980, 1999))
expand.unique$Var1 <- as.character(expand.unique$Var1)

# split combined district/county combinations into two columns
expand.unique$Var1b <- sub('-', ' ', expand.unique$Var1)
unique.split        <- strsplit(expand.unique$Var1b, ' ')
unique.splits       <- matrix(unlist(unique.split), ncol=2, byrow=TRUE, dimnames = list(NULL, c("district", "county")))

# create template prior to merging with original data set
state <- 'AA'
desired.resultb <- data.frame(state, expand.unique, unique.splits)

# merge template with original data set so missing observations are present if a county is not included for a given year
desired.resultc <- merge(df.1, desired.resultb, by = c('state', 'year', 'district', 'county'), all=TRUE)
desired.resultc

# compare output with a priori desired result
desired.result <- desired.result[order(desired.result$state, desired.result$year, desired.result$district, desired.result$county),]
all.equal(desired.result[,c(1,4,2,3,5)], desired.resultc[,1:5])

推荐答案

#find all (unique) state-district-county combinations
df.2 <- unique(df.1[,c("state","district","county")])

#find all (unique) years
df.3 <- unique(df.1[,"year",drop=FALSE])

#Cartesian product of combinations
df.4 <- merge(df.2,df.3)

#merge this with the original data frame,
#leaving NA's for unmatched parts in df.4
merge(df.1,df.4,all=TRUE)

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