XSLT组/合并子级(使用键) [英] XSLT Group/merge childs (using key)

问题描述

我试图了解如何使用我已经编写的代码来推导解决方案.

I am trying to understand how to deduce a solution using a code I already wrote.

为简化起见，我将首先解释我想做的事情和到目前为止所获得的成就.

In order to simplify I will explain first what I want to do and what I got so far.

假设我在XSLT中有一个XML变量，其中包含几个具有相同title属性的节点.

Suppose I have an XML variable in XSLT containing few nodes with the same title attribute.

使用 @Dimitre Novatchev解决方案设法将它们组合成一个节点.

Using @Dimitre Novatchev solution I have managed to combine them into one node.

所以，如果我有:

<t>
    <GroupData ID="xxx" Key="4" Temp="yyy">
        <ItemData ID="zzz" Value="3"/>
    </GroupData>
    <GroupData ID="yyy" Key="4" Temp="yyy">
        <ItemData ID="abc" Value="3"/>
    </GroupData>
    <GroupData ID="zzz" Temp="yyy">
        <ItemData ID="pqr" Value="1982"/>
    </GroupData>
    <GroupData ID="xxx" Key="4" Temp="yyy">
        <ItemData ID="www" Value="1982"/>
    </GroupData>
    <GroupData ID="yyy" Key="4" Temp="yyy">
        <ItemData ID="def" Value="1982"/>
    </GroupData>
    <GroupData ID="zzz" Temp="yyy">
        <ItemData ID="tuv" Value="1982"/>
    </GroupData>
</t>

使用以下键之后

<xsl:key name="kGDByIdKey" match="GroupData" use="concat(@ID, '+', @Key)"/>

我会得到:

<t>
   <GroupData ID="xxx" Key="4" Temp="yyy">
      <ItemData ID="zzz" Value="3"/>
      <ItemData ID="www" Value="1982"/>
   </GroupData>
   <GroupData ID="yyy" Key="4" Temp="yyy">
      <ItemData ID="abc" Value="3"/>
      <ItemData ID="def" Value="1982"/>
   </GroupData>
   <GroupData ID="zzz" Temp="yyy">
      <ItemData ID="pqr" Value="1982"/>
      <ItemData ID="tuv" Value="1982"/>
   </GroupData>
</t>

现在，我想对此做一点修改，我希望能够根据自己的决定来合并/合并标题.考虑到这一点，在上面的示例中，我想将xxx和zzz定义在同一组中，尽管它们使用不同的标题(极端情况-在我的工作空间中，我将它们定义为相同-我可能会遇到更多类似这个).

Now I would like to modify this one a little bit, I would like to be able to merge/combine titles by my decision. In that in mind, in the example above I would like to define xxx and zzz to be in the same group although they are using a different title (Extreme cases - in my workspace I defined them to be identical - I might have more cases like this).

如果您能告诉我一般的操作方向，我将不胜感激(我想我需要修改密钥或使用其他方法-generate-id或其他方法).

I would appreciate if you can tell me what should be the direction to do it generally ( I suppose I need to modify my key or using alternative method - generate-id or something).

我发现自己只能实施需要很多不必要努力的不良解决方案.

I find myself implementing only bad solutions requiring a lot of unnecessary effort.

推荐答案

我猜这是XSLT1，这很可惜，因为它在XSLT2中看起来更好，但是无论如何，您基本上都需要确保要分组的节点结束用相同的键

I would guess this is XSLT1 which is a shame as it would look nicer in XSLT2 but anyway you basically need to ensure that nodes that you want to group together end up with the same key

<xsl:key name="kGDByIdKey" match="GroupData" use="concat(@ID, '+', @Key)"/>

只有具有相同的@ID和@key的事物才具有相同的use属性

things only get the same use attribute if they have the same @ID and @key

如果将其更改为

<xsl:key name="kGDByIdKey" match="GroupData[not(@ID='xxx')]" use="concat(@ID, '+', @Key)"/>
<xsl:key name="kGDByIdKey" match="GroupData[@ID='xxx'] use="concat('zzz', '+', @Key)"/>

然后将使用zzz为ID为xxx的节点建立索引(并因此进行分组)(当然，从该节点构造查找值时，您也需要进行类似的更改)

Then nodes with ID xxx will be indexed (and therefore grouped) with zzz (or course you need to make a similar change when you construct the lookup value from the node)

如果您使用的是xslt 2，则可以使用更简单的功能样式，将其扩展到多个这样的更改时，该样式可能不太笨拙

If you were using xslt 2you could use a simpler functional style that is perhaps less unweildy when extended to multiple such changes

<xsl:key name="kGDByIdKey" match="GroupData" use="concat(replace(@ID,'^xxx$','zzz'), '+', @Key)"/>

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