Ruby String用正则表达式拆分 [英] Ruby String split with regex

问题描述

这是 Ruby 1.8.7 ，但应与1.9.x相同

This is Ruby 1.8.7 but should be same as for 1.9.x

例如，我正在尝试分割字符串:

I am trying to split a string for example:

a = "foo.bar.size.split('.').last"
# trying to split into ["foo", "bar","split('.')","last"]

基本上将其拆分为代表的命令，我正在尝试使用Regexp进行操作，但不确定如何使用regexp

Basically splitting it in commands it represents, I am trying to do it with Regexp but not sure how, idea was to use regexp

a.split(/[a-z\(\)](\.)[a-z\(\)]/)

这里尝试使用组(\.)对其进行拆分，但这似乎不是一个好方法.

Here trying to use group (\.) to split it with but this seems not to be good approach.

推荐答案

我认为这可以做到:

a.split(/\.(?=[\w])/)

我不知道您对正则表达式有多少了解，但是(?=[\w])是一个前瞻性提示，仅当下一个字符是字母类型的字符时才匹配点".提前查找实际上不会获取与之匹配的文本.它只是看起来".因此，结果恰好是您要寻找的东西:

I don't know how much you know about regex, but the (?=[\w]) is a lookahead that says "only match the dot if the next character is a letter kind of character". A lookahead won't actually grab the text it matches. It just "looks". So the result is exactly what you're looking for:

> a.split(/\.(?=[\w])/)
 => ["foo", "bar", "size", "split('.')", "last"] 

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