Python解释器错误，x不带参数(给定1个) [英] Python interpreter error, x takes no arguments (1 given)

问题描述

我正在写一小段python作为作业，但我没有让它运行！我没有太多的Python经验，但是我知道很多Java. 我正在尝试实现粒子群优化算法，这就是我所拥有的:

I'm writing a small piece of python as a homework assignment, and I'm not getting it to run! I don't have that much Python-experience, but I know quite a lot of Java. I'm trying to implement a Particle Swarm Optimization algorithm, and here's what I have:

class Particle:    

    def __init__(self,domain,ID):
        self.ID = ID
        self.gbest = None
        self.velocity = []
        self.current = []
        self.pbest = []
        for x in range(len(domain)):
            self.current.append(random.randint(domain[x][0],domain[x][1])) 
            self.velocity.append(random.randint(domain[x][0],domain[x][1])) 
            self.pbestx = self.current          

    def updateVelocity():
    for x in range(0,len(self.velocity)):
        self.velocity[x] = 2*random.random()*(self.pbestx[x]-self.current[x]) + 2 * random.random()*(self.gbest[x]-self.current[x]) 


    def updatePosition():    
        for x in range(0,len(self.current)):
            self.current[x] = self.current[x] + self.velocity[x]    

    def updatePbest():
        if costf(self.current) < costf(self.best):
            self.best = self.current        

    def psoOptimize(domain,costf,noOfParticles=20, noOfRuns=30):
        particles = []
        for i in range(noOfParticles):    
            particle = Particle(domain,i)    
            particles.append(particle)    

        for i in range(noOfRuns):
            Globalgbest = []
            cost = 9999999999999999999
        for i in particles:    
        if costf(i.pbest) < cost:
                cost = costf(i.pbest)
            Globalgbest = i.pbest
            for particle in particles:
                particle.updateVelocity()
                particle.updatePosition()
                particle.updatePbest(costf)
                particle.gbest = Globalgbest    


        return determineGbest(particles,costf)

现在，我认为没有理由不起作用. 但是，当我运行它时，出现此错误:

Now, I see no reason why this shouldn't work. However, when I run it, I get this error:

"TypeError:updateVelocity()不接受任何参数(给定1个)"

我不明白！我没有给它任何参数！

I don't understand! I'm not giving it any arguments!

感谢您的帮助，

鼻窦

推荐答案

Python隐式将对象传递给方法调用，但是您需要为其显式声明参数.通常将其命名为self:

Python implicitly passes the object to method calls, but you need to explicitly declare the parameter for it. This is customarily named self:

def updateVelocity(self):

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