如何确定本机JavaScript对象是否具有属性/方法? [英] How to determine if Native JavaScript Object has a Property/Method?

问题描述

我认为这很简单:

if(typeof(Array.push) == 'undefined'){
  //not defined, prototype a version of the push method
  // Firefox never gets here, but IE/Safari/Chrome/etc. do, even though
  // the Array object has a push method!
}

它在Firefox， 中工作正常，但在IE，Chrome，Safari，Opera 中却不能，它们将本地Array对象的所有属性/方法都返回为"undefined" '使用此测试.

And it does work fine in Firefox, but not in IE, Chrome, Safari, Opera, they return all properties/methods of the native Array object as 'undefined' using this test.

.hasOwnProperty(prop)方法仅适用于实例...因此不起作用，但是通过反复试验，我注意到这是可行的.

The .hasOwnProperty( prop ) method only works on instances... so it doesn't work, but by trial and error I noticed that this works.

//this works in Firefox/IE(6,7,8)/Chrome/Safari/Opera
if(typeof(Array().push) == 'undefined'){
  //not defined, prototype a version of the push method
}

使用此语法确定本机对象/〜"JavaScript类"〜中是否存在属性/方法是否存在问题，或者有更好的方法吗?

Is there anything wrong with using this syntax to determine if a property/method exists on a Native Object / ~"JavaScript Class"~, or is there a better way to do this?

推荐答案

首先，typeof是运算符，而不是函数，因此不需要括号.其次，访问对象的原型.

First of all, typeof is an operator, not a function, so you don't need the parentheses. Secondly, access the object's prototype.

alert( typeof Array.prototype.push );
alert( typeof Array.prototype.foo );

执行typeof Array.push时，您正在测试Array对象本身是否具有push方法，而不是在Array实例具有push方法时进行测试.

When you execute typeof Array.push you are testing if the Array object itself has a push method, not if instances of Array have a push method.

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