Java隐式"this"方法中的参数? [英] Java implicit "this" parameter in method?
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问题描述
在Java编程语言中，对象上的方法调用是通过隐式传递对对象的引用来起作用并作为静态方法起作用的吗?
Within the programming language Java do method invocations on an object, work by implicitly passing a reference to the object to act on and working as static methods?
推荐答案
Details on how method invocation works can be found in the Java SE 7 JVM specification, section 3.7. For an instance method the this reference is passed as the first parameter. This reference is also used to select which method to invoke, since it might be overridden in a subclass, so it is a bit more complicated than a static method.
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