使用变量类名(PHP)访问静态方法 [英] accessing static methods using a variable class name (PHP)

问题描述

我正在尝试访问静态方法，但使用变量作为类名.这可能吗?我似乎对此有疑问.我希望能够做这样的事情:

I am trying to access a static method, but using a variable as the class name. Is this possible? I seem to be having issues with it. I want to be able to do something like this:

class foo {
    public static function bar() {
        echo 'test';
    }
}

$variable_class_name = 'foo';
$variable_class_name::bar();

我也希望能够使用静态变量进行类似的操作.

And I want to be able to do similar using static variables as well.

推荐答案

该语法仅在PHP 5.3和更高版本中受支持.以前的版本不了解该语法，因此会出现解析错误(T_PAAMAYIM_NEKUDOTAYIM指的是::运算符).

That syntax is only supported in PHP 5.3 and later. Previous versions don't understand that syntax, hence your parse error (T_PAAMAYIM_NEKUDOTAYIM refers to the :: operator).

在以前的版本中，您可以尝试call_user_func()，将包含类名及其方法名的数组传递给它:

In previous versions you can try call_user_func(), passing it an array containing the class name and its method name:

$variable_class_name = 'foo';
call_user_func(array($variable_class_name, 'bar'));

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