Java Midi音符通过音符的八度音符映射到字符串 [英] Java midi note to string mapping via octave of a note

问题描述

在我的项目中，我希望至少能够告知用户他们需要演奏的音符位于哪个字符串上.我可以得到音符及其八度，但正如我发现的那样，该音符及其八度可以出现在吉他指板的多个位置.

In my project I want to be able to at least inform the user what string the note they need to play is on. I can get the note and its octave but as I've discovered, that note and its octave can appear in multiple places on a guitar fret board.

所以我的问题是:是否有将Midi音符映射到吉他弦的声音?

So my question is: Is there anyway to map a midi note to a guitar string?

推荐答案

此处的代码获取MIDI音符值，并返回最靠近乐器末端的吉他指板上的位置.零零是一个开放的字符串.

Here's code that takes the MIDI note value and returns the position on the guitar fretboard closest to the end of the instrument. Fret zero is an open string.

static class Fingering {
    int string;
    int fret;

    public String toString() {
        return "String : " + stringNames[string] + ", fret : " + fret;
    }
}

static String[] stringNames = new String[] {"Low E", "A", "D", "G", "B", "High E"}; 

    /** Array showing guitar string's relative pitches, in semi-tones, with "0" being low E */
static int[] strings = new int[]{64, 69, 74, 79, 83, 88};



public static Fingering getIdealFingering(int note) {
            if (note < strings[0])
                throw new RuntimeException("Note " + note + " is not playable on a guitar in standard tuning.");

    Fingering result = new Fingering();

    int idealString = 0;
    for (int x = 1; x < strings.length; x++) {
        if (note < strings[x])
            break;
        idealString = x; 
    }

    result.string = idealString;
    result.fret = note - strings[idealString];

    return result;
}

public static void main(String[] args) {
    System.out.println(getIdealFingering(64));  // Low E
    System.out.println(getIdealFingering(66));  // F#
    System.out.println(getIdealFingering(72));  // C on A string
    System.out.println(getIdealFingering(76));  // E on D string
    System.out.println(getIdealFingering(88));  // guitar's high e string, open
    System.out.println(getIdealFingering(100)); // high E, 12th fret
    System.out.println(getIdealFingering(103)); // high G
}

结果:

String : Low E, fret : 0
String : Low E, fret : 2
String : A, fret : 3
String : D, fret : 2
String : High E, fret : 0
String : High E, fret : 12
String : High E, fret : 15

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