返回多个日历事件 [英] Return Multiple calendar events

问题描述

由@hmjd这里答案帮我设置多个对象的文本。不过，我现在已经运行到一个问题。一个日期可以有多个事件，我想显示所有的事件和他们相同的事件详细信息页的详细信息。我怎样才能做到这一点？

code：

 公共类事件
{
    公众最终字符串名称;
    公共最后弦乐称号;
    公共最后弦乐细节;    公共事件（最后弦乐a_name，
                 最后弦乐a_title，
                 最后弦乐a_details）
    {
        名称= a_name;
        标题= a_title;
        细节= a_details;
    }
};最终事件E = eventDetails（1,4）;
name.setText（e.name）;
title.setText（e.title）;
details.setText（e.details）;//事件的详细信息
公共事件eventDetails（INT男，INT D）{
    开关（米）{
        情况1：
            如果（D == 10）{
                返回新的事件（EVENT1，我的-TITLE1，mydetails1）;
            }
            如果（D == 28）{
                 返回新的事件（EVENT2，我的-TITLE1，mydetails1）;
                 返回新的事件（EVENT3，我的-TITLE2，mydetails2）; //添加在此日期另一个事件;显然这是不正确的做法。
            }            打破;    }    返回新的事件（default_my名2，default_my-TITLE2，default_mydetails2）;
}
 

解决方案

要存储由eventDetails返回的事件，你会做这样的事情：

 的ArrayList＆LT;事件＆GT; E =新的ArrayList＆LT;事件＆GT;（）;
e.add（eventDetails（1，4））; //这增加了一个事件到ArrayList
 

然后访问存储在ArrayList中E中的活动：

 事件1 = e.get（0）; //第一个事件ArrayList中
事件的两个= e.get（1）; ArrayList中//第二个事件
...
事件N = e.get（N）; ArrayList中第n //事件
 

如果你想的话明确，使这个充满活力的，而不是 e.get（0），你会遍历ArrayList的尺寸如下：

 的for（int i = 0; I＆LT; e.size（）;我++）
{
    事件EV = e.get（ⅰ）;
    ev.doSomething（）;
    ev.doSomethingElse（）;
}
 

The answer here by @hmjd helped me to set the text of multiple objects. But I have run into a problem now. A date can have multiple events and I would like to show all the events and their details on the same event details page. How can I do this?

Code:

public class Event
{
    public final String name;
    public final String title;
    public final String details;

    public Event(final String a_name,
                 final String a_title,
                 final String a_details)
    {
        name = a_name;
        title = a_title;
        details = a_details;
    }
};



final Event e = eventDetails(1, 4);
name.setText(e.name);
title.setText(e.title);
details.setText(e.details);

//event details
public Event eventDetails(int m, int d) {
    switch (m) {
        case 1:
            if (d == 10) {
                return new Event("event1", "my-title1", "mydetails1");
            }
            if (d == 28) {
                 return new Event("event2", "my-title1", "mydetails1");
                 return new Event("event3", "my-title2", "mydetails2"); //add another event on this date; obviously this is not the right way.
            }

            break;

    }

    return new Event("default_my-name2", "default_my-title2", "default_mydetails2");
}

解决方案

To store the events returned by eventDetails, you would do something like this:

ArrayList<Event> e = new ArrayList<Event>();
e.add(eventDetails(1, 4)); // This adds one event to the ArrayList

Then to access the Events stored in ArrayList e:

Event one = e.get(0); // First Event in the ArrayList
Event two = e.get(1); // Second Event in the ArrayList
...
Event n = e.get(n); // nth Event in the ArrayList

If you want to make this dynamic instead of explicitly saying e.get(0), you would loop over the size of the ArrayList as follows:

for (int i = 0; i < e.size(); i++)
{
    Event ev = e.get(i);
    ev.doSomething();
    ev.doSomethingElse();
}

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